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func_get_args

(PHP 4, PHP 5)

func_get_args --  Returns an array comprising a function's argument list

Description

array func_get_args ( void )

Returns an array in which each element is a copy of the corresponding member of the current user-defined function's argument list. func_get_args() will generate a warning if called from outside of a function definition. This function cannot be used directly as a function parameter. Instead, its result may be assigned to a variable, which can then be passed to the function.

注: This function returns a copy of the passed arguments only, and does not account for default (non-passed) arguments.

注: 因为本函数依赖于当前域来决定参数细节，因此不能用作函数参数。如果必须要传递这个值，将结果赋给一个变量，然后传递该变量。

<?php
function foo()
{
    $numargs = func_num_args();
    echo "Number of arguments: $numargs<br />\n";
    if ($numargs >= 2) {
        echo "Second argument is: " . func_get_arg(1) . "<br />\n";
    }
    $arg_list = func_get_args();
    for ($i = 0; $i < $numargs; $i++) {
        echo "Argument $i is: " . $arg_list[$i] . "<br />\n";
    }
}

foo(1, 2, 3);
?>

func_get_args() may be used in conjunction with func_num_args() and func_get_arg() to allow user-defined functions to accept variable-length argument lists.

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func_get_arg上一级func_num_args