这个 SPI 使用的样例演示了可视性规则. 在 src/test/regress/regress.c 和 contrib/spi 里有更复杂的例子.
这是一个非常简单的 SPI 使用的例子. 过程 execq 在其第一个参数里接收一个 SQL 查询, 第二个参数接收一个tcount(译注:元组个数), 用 SPI_exec 执行这个查询并且返回查询执行过的记录个数:
#include "executor/spi.h" /* this is what you need to work with SPI */ int execq(TEXT *sql, int cnt); int execq(TEXT *sql, int cnt) { char *query; int ret; int proc; /* Convert given TEXT object to a C string */ query = DatumGetCString(DirectFunctionCall1(TEXTout, PointerGetDatum(sql))); SPI_connect(); ret = SPI_exec(query, cnt); proc = SPI_processed; /* * 如果这是 SELECT 并且取出了一些元组 - * 通过 elog (INFO) 向调用者 RETURNS 元组 */ if ( ret == SPI_OK_SELECT && SPI_processed > 0 ) { TupleDesc tupdesc = SPI_tuptable->tupdesc; SPITupleTable *tuptable = SPI_tuptable; char buf[8192]; int i,j; for (j = 0; j < proc; j++) { HeapTuple tuple = tuptable->vals[j]; for (i = 1, buf[0] = 0; i <= tupdesc->natts; i++) spnrintf(buf + strlen (buf), sizeof(buf) - strlen(buf), " %s%s", SPI_getvalue(tuple, tupdesc, i), (i == tupdesc->natts) ? " " : " |"); elog (INFO, "EXECQ: %s", buf); } } SPI_finish(); pfree(query); return (proc); }
然后,编译并创建函数:
CREATE FUNCTION execq (TEXT, INTEGER) RETURNS INTEGER AS '...path_to_so' LANGUAGE C;
vac=> SELECT execq('CREATE TABLE a (x INTEGER)', 0); execq ----- 0 (1 row) vac=> INSERT INTO a VALUES (execq('INSERT INTO a VALUES (0)',0)); INSERT 167631 1 vac=> SELECT execq('SELECT * FROM a',0); INFO:EXECQ: 0 <<< inserted by execq INFO:EXECQ: 1 <<< value returned by execq and inserted by upper INSERT execq ----- 2 (1 row) vac=> SELECT execq('INSERT INTO a SELECT x + 2 FROM a',1); execq ----- 1 (1 row) vac=> SELECT execq('SELECT * FROM a', 10); INFO:EXECQ: 0 INFO:EXECQ: 1 INFO:EXECQ: 2 <<< 0 + 2, only one tuple inserted - as specified execq ----- 3 <<< 10 是最大值, 3 是元组实际数量 (1 row) vac=> delete FROM a; DELETE 3 vac=> INSERT INTO a VALUES (execq('SELECT * FROM a', 0) + 1); INSERT 167712 1 vac=> SELECT * FROM a; x - 1 <<< no tuples in a (0) + 1 (1 row) vac=> INSERT INTO a VALUES (execq('SELECT * FROM a', 0) + 1); INFO:EXECQ: 0 INSERT 167713 1 vac=> SELECT * FROM a; x - 1 2 <<< there was single tuple in a + 1 (2 rows) -- This demonstrates data changes visibility rule: vac=> INSERT INTO a SELECT execq('SELECT * FROM a', 0) * x FROM a; INFO:EXECQ: 1 INFO:EXECQ: 2 INFO:EXECQ: 1 INFO:EXECQ: 2 INFO:EXECQ: 2 INSERT 0 2 vac=> SELECT * FROM a; x - 1 2 2 <<< 2 tuples * 1 (x in first tuple) 6 <<< 3 tuples (2 + 1 just inserted) * 2 (x in second tuple) (4 rows) ^^^^^^^^ tuples visible to execq() in different invocations