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| Mirrors > Home > ILE Home > Th. List > Mathboxes > bd3an | GIF version | ||
| Description: A conjunction of three bounded formulas is bounded. (Contributed by BJ, 3-Oct-2019.) |
| Ref | Expression |
|---|---|
| bd3or.1 | ⊢ BOUNDED 𝜑 |
| bd3or.2 | ⊢ BOUNDED 𝜓 |
| bd3or.3 | ⊢ BOUNDED 𝜒 |
| Ref | Expression |
|---|---|
| bd3an | ⊢ BOUNDED (𝜑 ∧ 𝜓 ∧ 𝜒) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | bd3or.1 | . . . 4 ⊢ BOUNDED 𝜑 | |
| 2 | bd3or.2 | . . . 4 ⊢ BOUNDED 𝜓 | |
| 3 | 1, 2 | ax-bdan 10606 | . . 3 ⊢ BOUNDED (𝜑 ∧ 𝜓) |
| 4 | bd3or.3 | . . 3 ⊢ BOUNDED 𝜒 | |
| 5 | 3, 4 | ax-bdan 10606 | . 2 ⊢ BOUNDED ((𝜑 ∧ 𝜓) ∧ 𝜒) |
| 6 | df-3an 921 | . 2 ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ ((𝜑 ∧ 𝜓) ∧ 𝜒)) | |
| 7 | 5, 6 | bd0r 10616 | 1 ⊢ BOUNDED (𝜑 ∧ 𝜓 ∧ 𝜒) |
| Colors of variables: wff set class |
| Syntax hints: ∧ wa 102 ∧ w3a 919 BOUNDED wbd 10603 |
| This theorem was proved from axioms: ax-1 5 ax-2 6 ax-mp 7 ax-ia1 104 ax-ia2 105 ax-ia3 106 ax-bd0 10604 ax-bdan 10606 |
| This theorem depends on definitions: df-bi 115 df-3an 921 |
| This theorem is referenced by: (None) |
| Copyright terms: Public domain | W3C validator |