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| Mirrors > Home > ILE Home > Th. List > ibd | GIF version | ||
| Description: Deduction that converts a biconditional implied by one of its arguments, into an implication. (Contributed by NM, 26-Jun-2004.) |
| Ref | Expression |
|---|---|
| ibd.1 | ⊢ (𝜑 → (𝜓 → (𝜓 ↔ 𝜒))) |
| Ref | Expression |
|---|---|
| ibd | ⊢ (𝜑 → (𝜓 → 𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | ibd.1 | . 2 ⊢ (𝜑 → (𝜓 → (𝜓 ↔ 𝜒))) | |
| 2 | bi1 116 | . 2 ⊢ ((𝜓 ↔ 𝜒) → (𝜓 → 𝜒)) | |
| 3 | 1, 2 | syli 37 | 1 ⊢ (𝜑 → (𝜓 → 𝜒)) |
| Colors of variables: wff set class |
| Syntax hints: → wi 4 ↔ wb 103 |
| This theorem was proved from axioms: ax-1 5 ax-2 6 ax-mp 7 ax-ia1 104 |
| This theorem depends on definitions: df-bi 115 |
| This theorem is referenced by: pm5.21ndd 653 oibabs 833 sssnm 3546 |
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