Theorem mdandyvrx6 41154

Description: Given the exclusivities set in the hypotheses, there exist a proof where ch, th, ta, et exclude ze, si accordingly. (Contributed by Jarvin Udandy, 7-Sep-2016.)

Hypotheses

Ref	Expression
mdandyvrx6.1	|- ( ph \/_ ze )
mdandyvrx6.2	|- ( ps \/_ si )
mdandyvrx6.3	|- ( ch <-> ph )
mdandyvrx6.4	|- ( th <-> ps )
mdandyvrx6.5	|- ( ta <-> ps )
mdandyvrx6.6	|- ( et <-> ph )

Assertion

Ref	Expression
mdandyvrx6	|- ( ( ( ( ch \/_ ze ) /\ ( th \/_ si ) ) /\ ( ta \/_ si ) ) /\ ( et \/_ ze ) )

Proof of Theorem mdandyvrx6

Step	Hyp	Ref	Expression
1		mdandyvrx6.1	. . . . 5 |- ( ph \/_ ze )
2		mdandyvrx6.3	. . . . 5 |- ( ch <-> ph )
3	1, 2	axorbciffatcxorb 41072	. . . 4 |- ( ch \/_ ze )
4		mdandyvrx6.2	. . . . 5 |- ( ps \/_ si )
5		mdandyvrx6.4	. . . . 5 |- ( th <-> ps )
6	4, 5	axorbciffatcxorb 41072	. . . 4 |- ( th \/_ si )
7	3, 6	pm3.2i 471	. . 3 |- ( ( ch \/_ ze ) /\ ( th \/_ si ) )
8		mdandyvrx6.5	. . . 4 |- ( ta <-> ps )
9	4, 8	axorbciffatcxorb 41072	. . 3 |- ( ta \/_ si )
10	7, 9	pm3.2i 471	. 2 |- ( ( ( ch \/_ ze ) /\ ( th \/_ si ) ) /\ ( ta \/_ si ) )
11		mdandyvrx6.6	. . 3 |- ( et <-> ph )
12	1, 11	axorbciffatcxorb 41072	. 2 |- ( et \/_ ze )
13	10, 12	pm3.2i 471	1 |- ( ( ( ( ch \/_ ze ) /\ ( th \/_ si ) ) /\ ( ta \/_ si ) ) /\ ( et \/_ ze ) )

Syntax hints:   <-> wb 196   /\ wa 384   \/_ wxo 1464

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 197  df-an 386  df-xor 1465

This theorem is referenced by:  mdandyvrx9  41157