Theorem eqeq1dALT 2625

Description: Shorter proof of eqeq1d 2624 based on more axioms. (Contributed by NM, 27-Dec-1993.) (Revised by Wolf Lammen, 19-Nov-2019.) (Proof modification is discouraged.) (New usage is discouraged.)

Hypothesis

Ref	Expression
eqeq1d.1	⊢ (𝜑 → 𝐴 = 𝐵)

Assertion

Ref	Expression
eqeq1dALT	⊢ (𝜑 → (𝐴 = 𝐶 ↔ 𝐵 = 𝐶))

Proof of Theorem eqeq1dALT

Dummy variable 𝑥 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		eqeq1d.1	. . . . . 6 ⊢ (𝜑 → 𝐴 = 𝐵)
2		dfcleq 2616	. . . . . 6 ⊢ (𝐴 = 𝐵 ↔ ∀𝑥(𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐵))
3	1, 2	sylib 208	. . . . 5 ⊢ (𝜑 → ∀𝑥(𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐵))
4	3	19.21bi 2059	. . . 4 ⊢ (𝜑 → (𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐵))
5	4	bibi1d 333	. . 3 ⊢ (𝜑 → ((𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐶) ↔ (𝑥 ∈ 𝐵 ↔ 𝑥 ∈ 𝐶)))
6	5	albidv 1849	. 2 ⊢ (𝜑 → (∀𝑥(𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐶) ↔ ∀𝑥(𝑥 ∈ 𝐵 ↔ 𝑥 ∈ 𝐶)))
7		dfcleq 2616	. 2 ⊢ (𝐴 = 𝐶 ↔ ∀𝑥(𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐶))
8		dfcleq 2616	. 2 ⊢ (𝐵 = 𝐶 ↔ ∀𝑥(𝑥 ∈ 𝐵 ↔ 𝑥 ∈ 𝐶))
9	6, 7, 8	3bitr4g 303	1 ⊢ (𝜑 → (𝐴 = 𝐶 ↔ 𝐵 = 𝐶))

Syntax hints:   → wi 4   ↔ wb 196  ∀wal 1481   = wceq 1483   ∈ wcel 1990

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-9 1999  ax-12 2047  ax-ext 2602

This theorem depends on definitions:  df-bi 197  df-an 386  df-ex 1705  df-cleq 2615

This theorem is referenced by: (None)