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| Mirrors > Home > NFE Home > Th. List > syl5rbb | GIF version | ||
| Description: A syllogism inference from two biconditionals. (Contributed by NM, 5-Aug-1993.) |
| Ref | Expression |
|---|---|
| syl5rbb.1 | ⊢ (φ ↔ ψ) |
| syl5rbb.2 | ⊢ (χ → (ψ ↔ θ)) |
| Ref | Expression |
|---|---|
| syl5rbb | ⊢ (χ → (θ ↔ φ)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | syl5rbb.1 | . . 3 ⊢ (φ ↔ ψ) | |
| 2 | syl5rbb.2 | . . 3 ⊢ (χ → (ψ ↔ θ)) | |
| 3 | 1, 2 | syl5bb 248 | . 2 ⊢ (χ → (φ ↔ θ)) |
| 4 | 3 | bicomd 192 | 1 ⊢ (χ → (θ ↔ φ)) |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 ↔ wb 176 |
| This theorem was proved from axioms: ax-1 5 ax-2 6 ax-3 7 ax-mp 8 |
| This theorem depends on definitions: df-bi 177 |
| This theorem is referenced by: syl5rbbr 251 csbabg 3197 uniiunlem 3353 opkelimagekg 4271 setswith 4321 fnresdisj 5193 f1oiso 5499 |
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