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Theorem ska2b 227
Description: Axiom KA2b in Pavicic and Megill, 1998
Assertion
Ref Expression
ska2b (((a v c) == (b v c)) == ((a' ^ c')' == (b' ^ c')')) = 1

Proof of Theorem ska2b
StepHypRef Expression
1 oran 87 . . 3 (a v c) = (a' ^ c')'
2 oran 87 . . 3 (b v c) = (b' ^ c')'
31, 22bi 99 . 2 ((a v c) == (b v c)) = ((a' ^ c')' == (b' ^ c')')
43bi1 118 1 (((a v c) == (b v c)) == ((a' ^ c')' == (b' ^ c')')) = 1
Colors of variables: term
Syntax hints:   = wb 1  'wn 4   == tb 5   v wo 6   ^ wa 7  1wt 8
This theorem was proved from axioms:  ax-a1 30  ax-a2 31  ax-a5 34  ax-r1 35  ax-r2 36  ax-r4 37  ax-r5 38
This theorem depends on definitions:  df-b 39  df-a 40  df-t 41  df-f 42
This theorem is referenced by: (None)
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