Function std::boxed::into_raw

pub fn into_raw<T>(b: Box<T>) -> *mut T where T: ?Sized

Deprecated since 1.2.0

: renamed to Box::into_raw

Consumes the Box, returning the wrapped raw pointer.

After call to this function, caller is responsible for the memory previously managed by Box, in particular caller should properly destroy T and release memory. The proper way to do it is to convert pointer back to Box with Box::from_raw function, because Box does not specify, how memory is allocated.

Examples

#![feature(box_raw)] fn main() { use std::boxed; let seventeen = Box::new(17u32); let raw = boxed::into_raw(seventeen); let boxed_again = unsafe { Box::from_raw(raw) }; }

#![feature(box_raw)]

use std::boxed;

let seventeen = Box::new(17u32);
let raw = boxed::into_raw(seventeen);
let boxed_again = unsafe { Box::from_raw(raw) };