GNU Octave  4.0.0
A high-level interpreted language, primarily intended for numerical computations, mostly compatible with Matlab
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zpassf4.f
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1  subroutine zpassf4 (ido,l1,cc,ch,wa1,wa2,wa3)
2  implicit double precision (a-h,o-z)
3  dimension cc(ido,4,l1) ,ch(ido,l1,4) ,
4  1 wa1(1) ,wa2(1) ,wa3(1)
5  if (ido .ne. 2) go to 102
6  do 101 k=1,l1
7  ti1 = cc(2,1,k)-cc(2,3,k)
8  ti2 = cc(2,1,k)+cc(2,3,k)
9  tr4 = cc(2,2,k)-cc(2,4,k)
10  ti3 = cc(2,2,k)+cc(2,4,k)
11  tr1 = cc(1,1,k)-cc(1,3,k)
12  tr2 = cc(1,1,k)+cc(1,3,k)
13  ti4 = cc(1,4,k)-cc(1,2,k)
14  tr3 = cc(1,2,k)+cc(1,4,k)
15  ch(1,k,1) = tr2+tr3
16  ch(1,k,3) = tr2-tr3
17  ch(2,k,1) = ti2+ti3
18  ch(2,k,3) = ti2-ti3
19  ch(1,k,2) = tr1+tr4
20  ch(1,k,4) = tr1-tr4
21  ch(2,k,2) = ti1+ti4
22  ch(2,k,4) = ti1-ti4
23  101 continue
24  return
25  102 do 104 k=1,l1
26  do 103 i=2,ido,2
27  ti1 = cc(i,1,k)-cc(i,3,k)
28  ti2 = cc(i,1,k)+cc(i,3,k)
29  ti3 = cc(i,2,k)+cc(i,4,k)
30  tr4 = cc(i,2,k)-cc(i,4,k)
31  tr1 = cc(i-1,1,k)-cc(i-1,3,k)
32  tr2 = cc(i-1,1,k)+cc(i-1,3,k)
33  ti4 = cc(i-1,4,k)-cc(i-1,2,k)
34  tr3 = cc(i-1,2,k)+cc(i-1,4,k)
35  ch(i-1,k,1) = tr2+tr3
36  cr3 = tr2-tr3
37  ch(i,k,1) = ti2+ti3
38  ci3 = ti2-ti3
39  cr2 = tr1+tr4
40  cr4 = tr1-tr4
41  ci2 = ti1+ti4
42  ci4 = ti1-ti4
43  ch(i-1,k,2) = wa1(i-1)*cr2+wa1(i)*ci2
44  ch(i,k,2) = wa1(i-1)*ci2-wa1(i)*cr2
45  ch(i-1,k,3) = wa2(i-1)*cr3+wa2(i)*ci3
46  ch(i,k,3) = wa2(i-1)*ci3-wa2(i)*cr3
47  ch(i-1,k,4) = wa3(i-1)*cr4+wa3(i)*ci4
48  ch(i,k,4) = wa3(i-1)*ci4-wa3(i)*cr4
49  103 continue
50  104 continue
51  return
52  end
std::string dimension(void) const
subroutine zpassf4(ido, l1, cc, ch, wa1, wa2, wa3)
Definition: zpassf4.f:1