第 23 章 示例:复杂映射实例

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第 23 章 示例:复杂映射实例

23.1. Employer(雇主)/Employee(雇员)
23.2. Author(作家)/Work(作品)
23.3. Customer(客户)/Order(订单)/Product(产品)
23.4. 杂例
23.4.1. "Typed" one-to-one association
23.4.2. Composite key example
23.4.3. 共有组合键属性的多对多(Many-to-many with shared composite key attribute)
23.4.4. Content based discrimination
23.4.5. Associations on alternate keys

This chapters explores some more complex association mappings.

The following model of the relationship between Employer and Employee uses an entity class (Employment) to represent the association. You can do this when there might be more than one period of employment for the same two parties. Components are used to model monetary values and employee names.

Here is a possible mapping document:

<hibernate-mapping>
        
    <class name="Employer" table="employers">
        <id name="id">
            <generator class="sequence">
                <param name="sequence">employer_id_seq</param>
            </generator>
        </id>
        <property name="name"/>
    </class>

    <class name="Employment" table="employment_periods">

        <id name="id">
            <generator class="sequence">
                <param name="sequence">employment_id_seq</param>
            </generator>
        </id>
        <property name="startDate" column="start_date"/>
        <property name="endDate" column="end_date"/>

        <component name="hourlyRate" class="MonetaryAmount">
            <property name="amount">
                <column name="hourly_rate" sql-type="NUMERIC(12, 2)"/>
            </property>
            <property name="currency" length="12"/>
        </component>

        <many-to-one name="employer" column="employer_id" not-null="true"/>
        <many-to-one name="employee" column="employee_id" not-null="true"/>

    </class>

    <class name="Employee" table="employees">
        <id name="id">
            <generator class="sequence">
                <param name="sequence">employee_id_seq</param>
            </generator>
        </id>
        <property name="taxfileNumber"/>
        <component name="name" class="Name">
            <property name="firstName"/>
            <property name="initial"/>
            <property name="lastName"/>
        </component>
    </class>

</hibernate-mapping>

Here is the table schema generated by SchemaExport.

create table employers (
    id BIGINT not null, 
    name VARCHAR(255), 
    primary key (id)
)

create table employment_periods (
    id BIGINT not null,
    hourly_rate NUMERIC(12, 2),
    currency VARCHAR(12), 
    employee_id BIGINT not null, 
    employer_id BIGINT not null, 
    end_date TIMESTAMP, 
    start_date TIMESTAMP, 
    primary key (id)
)

create table employees (
    id BIGINT not null, 
    firstName VARCHAR(255), 
    initial CHAR(1), 
    lastName VARCHAR(255), 
    taxfileNumber VARCHAR(255), 
    primary key (id)
)

alter table employment_periods 
    add constraint employment_periodsFK0 foreign key (employer_id) references employers
alter table employment_periods 
    add constraint employment_periodsFK1 foreign key (employee_id) references employees
create sequence employee_id_seq
create sequence employment_id_seq
create sequence employer_id_seq

Consider the following model of the relationships between Work, Author and Person. In the example, the relationship between Work and Author is represented as a many-to-many association and the relationship between Author and Person is represented as one-to-one association. Another possibility would be to have Author extend Person.

下面的映射文件正确的描述了这些关系:

<hibernate-mapping>

    <class name="Work" table="works" discriminator-value="W">

        <id name="id" column="id">
            <generator class="native"/>
        </id>
        <discriminator column="type" type="character"/>

        <property name="title"/>
        <set name="authors" table="author_work">
            <key column name="work_id"/>
            <many-to-many class="Author" column name="author_id"/>
        </set>

        <subclass name="Book" discriminator-value="B">
            <property name="text"/>
        </subclass>

        <subclass name="Song" discriminator-value="S">
            <property name="tempo"/>
            <property name="genre"/>
        </subclass>

    </class>

    <class name="Author" table="authors">

        <id name="id" column="id">
            <!-- The Author must have the same identifier as the Person -->
            <generator class="assigned"/> 
        </id>

        <property name="alias"/>
        <one-to-one name="person" constrained="true"/>

        <set name="works" table="author_work" inverse="true">
            <key column="author_id"/>
            <many-to-many class="Work" column="work_id"/>
        </set>

    </class>

    <class name="Person" table="persons">
        <id name="id" column="id">
            <generator class="native"/>
        </id>
        <property name="name"/>
    </class>

</hibernate-mapping>

There are four tables in this mapping: works, authors and persons hold work, author and person data respectively. author_work is an association table linking authors to works. Here is the table schema, as generated by SchemaExport:

create table works (
    id BIGINT not null generated by default as identity, 
    tempo FLOAT, 
    genre VARCHAR(255), 
    text INTEGER, 
    title VARCHAR(255), 
    type CHAR(1) not null, 
    primary key (id)
)

create table author_work (
    author_id BIGINT not null, 
    work_id BIGINT not null, 
    primary key (work_id, author_id)
)

create table authors (
    id BIGINT not null generated by default as identity, 
    alias VARCHAR(255), 
    primary key (id)
)

create table persons (
    id BIGINT not null generated by default as identity, 
    name VARCHAR(255), 
    primary key (id)
)

alter table authors 
    add constraint authorsFK0 foreign key (id) references persons
alter table author_work 
    add constraint author_workFK0 foreign key (author_id) references authors
alter table author_work
    add constraint author_workFK1 foreign key (work_id) references works

In this section we consider a model of the relationships between Customer, Order, Line Item and Product. There is a one-to-many association between Customer and Order, but how can you represent Order / LineItem / Product? In the example, LineItem is mapped as an association class representing the many-to-many association between Order and Product. In Hibernate this is called a composite element.

The mapping document will look like this:

<hibernate-mapping>

    <class name="Customer" table="customers">
        <id name="id">
            <generator class="native"/>
        </id>
        <property name="name"/>
        <set name="orders" inverse="true">
            <key column="customer_id"/>
            <one-to-many class="Order"/>
        </set>
    </class>

    <class name="Order" table="orders">
        <id name="id">
            <generator class="native"/>
        </id>
        <property name="date"/>
        <many-to-one name="customer" column="customer_id"/>
        <list name="lineItems" table="line_items">
            <key column="order_id"/>
            <list-index column="line_number"/>
            <composite-element class="LineItem">
                <property name="quantity"/>
                <many-to-one name="product" column="product_id"/>
            </composite-element>
        </list>
    </class>

    <class name="Product" table="products">
        <id name="id">
            <generator class="native"/>
        </id>
        <property name="serialNumber"/>
    </class>

</hibernate-mapping>

customers, orders, line_itemsproducts 分别保存着customer, order, order line item 和 product的数据。 line_items也作为连接orders 和 products的关联表。

create table customers (
    id BIGINT not null generated by default as identity, 
    name VARCHAR(255), 
    primary key (id)
)

create table orders (
    id BIGINT not null generated by default as identity, 
    customer_id BIGINT, 
    date TIMESTAMP, 
    primary key (id)
)

create table line_items (
    line_number INTEGER not null, 
    order_id BIGINT not null, 
    product_id BIGINT, 
    quantity INTEGER, 
    primary key (order_id, line_number)
)

create table products (
    id BIGINT not null generated by default as identity, 
    serialNumber VARCHAR(255), 
    primary key (id)
)

alter table orders 
    add constraint ordersFK0 foreign key (customer_id) references customers
alter table line_items
    add constraint line_itemsFK0 foreign key (product_id) references products
alter table line_items
    add constraint line_itemsFK1 foreign key (order_id) references orders

These examples are available from the Hibernate test suite. You will find many other useful example mappings there by searching in the test folder of the Hibernate distribution.

<class name="Customer">

    <id name="customerId"
        length="10">
        <generator class="assigned"/>
    </id>

    <property name="name" not-null="true" length="100"/>
    <property name="address" not-null="true" length="200"/>

    <list name="orders"
            inverse="true"
            cascade="save-update">
        <key column="customerId"/>
        <index column="orderNumber"/>
        <one-to-many class="Order"/>
    </list>

</class>

<class name="Order" table="CustomerOrder" lazy="true">
    <synchronize table="LineItem"/>
    <synchronize table="Product"/>
    
    <composite-id name="id" 
            class="Order$Id">
        <key-property name="customerId" length="10"/>
        <key-property name="orderNumber"/>
    </composite-id>
    
    <property name="orderDate" 
            type="calendar_date"
            not-null="true"/>
    
    <property name="total">
        <formula>
            ( select sum(li.quantity*p.price) 
            from LineItem li, Product p 
            where li.productId = p.productId 
                and li.customerId = customerId 
                and li.orderNumber = orderNumber )
        </formula>
    </property>
    
    <many-to-one name="customer"
            column="customerId"
            insert="false"
            update="false" 
            not-null="true"/>
        
    <bag name="lineItems"
            fetch="join" 
            inverse="true"
            cascade="save-update">
        <key>
            <column name="customerId"/>
            <column name="orderNumber"/>
        </key>
        <one-to-many class="LineItem"/>
    </bag>
    
</class>
    
<class name="LineItem">
    
    <composite-id name="id" 
            class="LineItem$Id">
        <key-property name="customerId" length="10"/>
        <key-property name="orderNumber"/>
        <key-property name="productId" length="10"/>
    </composite-id>
    
    <property name="quantity"/>
    
    <many-to-one name="order"
            insert="false"
            update="false" 
            not-null="true">
        <column name="customerId"/>
        <column name="orderNumber"/>
    </many-to-one>
    
    <many-to-one name="product"
            insert="false"
            update="false" 
            not-null="true"
            column="productId"/>
        
</class>

<class name="Product">
    <synchronize table="LineItem"/>

    <id name="productId"
        length="10">
        <generator class="assigned"/>
    </id>
    
    <property name="description" 
        not-null="true" 
        length="200"/>
    <property name="price" length="3"/>
    <property name="numberAvailable"/>
    
    <property name="numberOrdered">
        <formula>
            ( select sum(li.quantity) 
            from LineItem li 
            where li.productId = productId )
        </formula>
    </property>
    
</class>