Theorem xoror 1310

Description: XOR implies OR. (Contributed by BJ, 19-Apr-2019.)

Assertion

Ref	Expression
xoror	|- ( ( ph \/_ ps ) -> ( ph \/ ps ) )

Proof of Theorem xoror

Step	Hyp	Ref	Expression
1		xoranor 1308	. 2 |- ( ( ph \/_ ps ) <-> ( ( ph \/ ps ) /\ ( -. ph \/ -. ps ) ) )
2	1	simplbi 268	1 |- ( ( ph \/_ ps ) -> ( ph \/ ps ) )

Syntax hints:   -. wn 3   -> wi 4   \/ wo 661   \/_ wxo 1306

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-in1 576  ax-in2 577  ax-io 662

This theorem depends on definitions:  df-bi 115  df-xor 1307

This theorem is referenced by:  mtpxor  1357