Theorem sseqtrd 3035

Description: Substitution of equality into a subclass relationship. (Contributed by NM, 25-Apr-2004.)

Hypotheses

Ref	Expression
sseqtrd.1	⊢ (𝜑 → 𝐴 ⊆ 𝐵)
sseqtrd.2	⊢ (𝜑 → 𝐵 = 𝐶)

Assertion

Ref	Expression
sseqtrd	⊢ (𝜑 → 𝐴 ⊆ 𝐶)

Proof of Theorem sseqtrd

Step	Hyp	Ref	Expression
1		sseqtrd.1	. 2 ⊢ (𝜑 → 𝐴 ⊆ 𝐵)
2		sseqtrd.2	. . 3 ⊢ (𝜑 → 𝐵 = 𝐶)
3	2	sseq2d 3027	. 2 ⊢ (𝜑 → (𝐴 ⊆ 𝐵 ↔ 𝐴 ⊆ 𝐶))
4	1, 3	mpbid 145	1 ⊢ (𝜑 → 𝐴 ⊆ 𝐶)

Syntax hints:   → wi 4   = wceq 1284   ⊆ wss 2973

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-5 1376  ax-7 1377  ax-gen 1378  ax-ie1 1422  ax-ie2 1423  ax-8 1435  ax-11 1437  ax-4 1440  ax-17 1459  ax-i9 1463  ax-ial 1467  ax-i5r 1468  ax-ext 2063

This theorem depends on definitions:  df-bi 115  df-nf 1390  df-sb 1686  df-clab 2068  df-cleq 2074  df-clel 2077  df-in 2979  df-ss 2986

This theorem is referenced by:  sseqtr4d  3036  resasplitss  5089  nnaword2  6110  erssxp  6152  phpm  6351  ioodisj  9015