Users' Mathboxes Mathbox for BJ < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >   Mathboxes  >  bj-vjust Structured version   Visualization version   Unicode version

Theorem bj-vjust 32786
Description: Remove dependency on ax-13 2246 from vjust 3201 (note the absence of DV conditions). Soundness justification theorem for df-v 3202. (Contributed by BJ, 31-May-2019.) (Proof modification is discouraged.)
Assertion
Ref Expression
bj-vjust  |-  { x  |  x  =  x }  =  { y  |  y  =  y }

Proof of Theorem bj-vjust
Dummy variable  z is distinct from all other variables.
StepHypRef Expression
1 equid 1939 . . . . 5  |-  x  =  x
21bj-sbtv 32766 . . . 4  |-  [ z  /  x ] x  =  x
3 equid 1939 . . . . 5  |-  y  =  y
43bj-sbtv 32766 . . . 4  |-  [ z  /  y ] y  =  y
52, 42th 254 . . 3  |-  ( [ z  /  x ]
x  =  x  <->  [ z  /  y ] y  =  y )
6 df-clab 2609 . . 3  |-  ( z  e.  { x  |  x  =  x }  <->  [ z  /  x ]
x  =  x )
7 df-clab 2609 . . 3  |-  ( z  e.  { y  |  y  =  y }  <->  [ z  /  y ] y  =  y )
85, 6, 73bitr4i 292 . 2  |-  ( z  e.  { x  |  x  =  x }  <->  z  e.  { y  |  y  =  y } )
98eqriv 2619 1  |-  { x  |  x  =  x }  =  { y  |  y  =  y }
Colors of variables: wff setvar class
Syntax hints:    = wceq 1483   [wsb 1880    e. wcel 1990   {cab 2608
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-9 1999  ax-12 2047  ax-ext 2602
This theorem depends on definitions:  df-bi 197  df-an 386  df-ex 1705  df-sb 1881  df-clab 2609  df-cleq 2615
This theorem is referenced by: (None)
  Copyright terms: Public domain W3C validator