Theorem cdeqth 3422

Description: Deduce conditional equality from a theorem. (Contributed by Mario Carneiro, 11-Aug-2016.)

Hypothesis

Ref	Expression
cdeqth.1	|- ph

Assertion

Ref	Expression
cdeqth	|- CondEq ( x = y -> ph )

Proof of Theorem cdeqth

Step	Hyp	Ref	Expression
1		cdeqth.1	. . 3 |- ph
2	1	a1i 11	. 2 |- ( x = y -> ph )
3	2	cdeqi 3420	1 |- CondEq ( x = y -> ph )

Syntax hints:  CondEqwcdeq 3418

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 197  df-cdeq 3419

This theorem is referenced by:  cdeqal1  3426  cdeqab1  3427  nfccdeq  3433