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Theorem nfnf 2158
Description: If  x is not free in  ph, it is not free in  F/ y ph. (Contributed by Mario Carneiro, 11-Aug-2016.) (Proof shortened by Wolf Lammen, 30-Dec-2017.)
Hypothesis
Ref Expression
nfnf.1  |-  F/ x ph
Assertion
Ref Expression
nfnf  |-  F/ x F/ y ph

Proof of Theorem nfnf
StepHypRef Expression
1 df-nf 1710 . 2  |-  ( F/ y ph  <->  ( E. y ph  ->  A. y ph ) )
2 nfnf.1 . . . 4  |-  F/ x ph
32nfex 2154 . . 3  |-  F/ x E. y ph
42nfal 2153 . . 3  |-  F/ x A. y ph
53, 4nfim 1825 . 2  |-  F/ x
( E. y ph  ->  A. y ph )
61, 5nfxfr 1779 1  |-  F/ x F/ y ph
Colors of variables: wff setvar class
Syntax hints:    -> wi 4   A.wal 1481   E.wex 1704   F/wnf 1708
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-10 2019  ax-11 2034  ax-12 2047
This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-ex 1705  df-nf 1710
This theorem is referenced by:  nfnfc  2774  nfnfcALT  2775  bj-nfnfc  32853  bj-nfcf  32920
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