Theorem bj-ralcom4 32868

Description: Remove from ralcom4 3224 dependency on ax-ext 2602 and ax-13 2246 (and on df-or 385, df-an 386, df-tru 1486, df-sb 1881, df-clab 2609, df-cleq 2615, df-clel 2618, df-nfc 2753, df-v 3202). This proof uses only df-ral 2917 on top of first-order logic. (Contributed by BJ, 13-Jun-2019.) (Proof modification is discouraged.)

Assertion

Ref	Expression
bj-ralcom4	⊢ (∀𝑥 ∈ 𝐴 ∀𝑦𝜑 ↔ ∀𝑦∀𝑥 ∈ 𝐴 𝜑)

Distinct variable groups:   𝑥,𝑦   𝑦,𝐴

Allowed substitution hints:   𝜑(𝑥,𝑦)   𝐴(𝑥)

Proof of Theorem bj-ralcom4

Step	Hyp	Ref	Expression
1		19.21v 1868	. . . . 5 ⊢ (∀𝑦(𝑥 ∈ 𝐴 → 𝜑) ↔ (𝑥 ∈ 𝐴 → ∀𝑦𝜑))
2	1	bicomi 214	. . . 4 ⊢ ((𝑥 ∈ 𝐴 → ∀𝑦𝜑) ↔ ∀𝑦(𝑥 ∈ 𝐴 → 𝜑))
3	2	albii 1747	. . 3 ⊢ (∀𝑥(𝑥 ∈ 𝐴 → ∀𝑦𝜑) ↔ ∀𝑥∀𝑦(𝑥 ∈ 𝐴 → 𝜑))
4		alcom 2037	. . 3 ⊢ (∀𝑥∀𝑦(𝑥 ∈ 𝐴 → 𝜑) ↔ ∀𝑦∀𝑥(𝑥 ∈ 𝐴 → 𝜑))
5	3, 4	bitri 264	. 2 ⊢ (∀𝑥(𝑥 ∈ 𝐴 → ∀𝑦𝜑) ↔ ∀𝑦∀𝑥(𝑥 ∈ 𝐴 → 𝜑))
6		df-ral 2917	. 2 ⊢ (∀𝑥 ∈ 𝐴 ∀𝑦𝜑 ↔ ∀𝑥(𝑥 ∈ 𝐴 → ∀𝑦𝜑))
7		df-ral 2917	. . 3 ⊢ (∀𝑥 ∈ 𝐴 𝜑 ↔ ∀𝑥(𝑥 ∈ 𝐴 → 𝜑))
8	7	albii 1747	. 2 ⊢ (∀𝑦∀𝑥 ∈ 𝐴 𝜑 ↔ ∀𝑦∀𝑥(𝑥 ∈ 𝐴 → 𝜑))
9	5, 6, 8	3bitr4i 292	1 ⊢ (∀𝑥 ∈ 𝐴 ∀𝑦𝜑 ↔ ∀𝑦∀𝑥 ∈ 𝐴 𝜑)

Syntax hints:   → wi 4   ↔ wb 196  ∀wal 1481   ∈ wcel 1990  ∀wral 2912

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-11 2034

This theorem depends on definitions:  df-bi 197  df-ex 1705  df-ral 2917

This theorem is referenced by: (None)