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Theorem dp35lemg 1169
Description: Part of proof (3)=>(5) in Day/Pickering 1982.
Hypotheses
Ref Expression
dp35lem.1 c0 = ((a1 v a2) ^ (b1 v b2))
dp35lem.2 c1 = ((a0 v a2) ^ (b0 v b2))
dp35lem.3 c2 = ((a0 v a1) ^ (b0 v b1))
dp35lem.4 p0 = ((a1 v b1) ^ (a2 v b2))
dp35lem.5 p = (((a0 v b0) ^ (a1 v b1)) ^ (a2 v b2))
Assertion
Ref Expression
dp35lemg p =< (a0 v (b0 ^ (b1 v (c2 ^ (c0 v c1)))))

Proof of Theorem dp35lemg
StepHypRef Expression
1 dp35lem.1 . 2 c0 = ((a1 v a2) ^ (b1 v b2))
2 dp35lem.2 . 2 c1 = ((a0 v a2) ^ (b0 v b2))
3 dp35lem.3 . 2 c2 = ((a0 v a1) ^ (b0 v b1))
4 dp35lem.5 . 2 p = (((a0 v b0) ^ (a1 v b1)) ^ (a2 v b2))
51, 2, 3, 4dp53 1168 1 p =< (a0 v (b0 ^ (b1 v (c2 ^ (c0 v c1)))))
Colors of variables: term
Syntax hints:   = wb 1   =< wle 2   v wo 6   ^ wa 7
This theorem was proved from axioms:  ax-a1 30  ax-a2 31  ax-a3 32  ax-a4 33  ax-a5 34  ax-r1 35  ax-r2 36  ax-r4 37  ax-r5 38  ax-ml 1120  ax-arg 1151
This theorem depends on definitions:  df-a 40  df-t 41  df-f 42  df-le1 130  df-le2 131
This theorem is referenced by:  dp35lemf  1170
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