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Theorem i1i2con1 268
Description: Correspondence between Sasaki and Dishkant conditionals.
Assertion
Ref Expression
i1i2con1 (a ->1 b') = (b ->2 a')

Proof of Theorem i1i2con1
StepHypRef Expression
1 i1i2 266 . 2 (a ->1 b') = (b'' ->2 a')
2 ax-a1 30 . . . 4 b = b''
32ax-r1 35 . . 3 b'' = b
43ud2lem0b 259 . 2 (b'' ->2 a') = (b ->2 a')
51, 4ax-r2 36 1 (a ->1 b') = (b ->2 a')
Colors of variables: term
Syntax hints:   = wb 1  'wn 4   ->1 wi1 12   ->2 wi2 13
This theorem was proved from axioms:  ax-a1 30  ax-a2 31  ax-r1 35  ax-r2 36  ax-r4 37  ax-r5 38
This theorem depends on definitions:  df-a 40  df-i1 44  df-i2 45
This theorem is referenced by: (None)
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