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Theorem wle0 390
Description: 0 is l.e. anything.
Assertion
Ref Expression
wle0 (0 =<2 a) = 1

Proof of Theorem wle0
StepHypRef Expression
1 df-le 129 . 2 (0 =<2 a) = ((0 v a) == a)
2 ax-a2 31 . . . 4 (0 v a) = (a v 0)
3 or0 102 . . . 4 (a v 0) = a
42, 3ax-r2 36 . . 3 (0 v a) = a
54bi1 118 . 2 ((0 v a) == a) = 1
61, 5ax-r2 36 1 (0 =<2 a) = 1
Colors of variables: term
Syntax hints:   = wb 1   == tb 5   v wo 6  1wt 8  0wf 9   =<2 wle2 10
This theorem was proved from axioms:  ax-a1 30  ax-a2 31  ax-a5 34  ax-r1 35  ax-r2 36  ax-r4 37  ax-r5 38
This theorem depends on definitions:  df-b 39  df-a 40  df-t 41  df-f 42  df-le 129
This theorem is referenced by: (None)
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