Theorem 4p1e5 8168

Description: 4 + 1 = 5. (Contributed by Mario Carneiro, 18-Apr-2015.)

Assertion

Ref	Expression
4p1e5	|- ( 4 + 1 ) = 5

Proof of Theorem 4p1e5

Step	Hyp	Ref	Expression
1		df-5 8101	. 2 |- 5 = ( 4 + 1 )
2	1	eqcomi 2085	1 |- ( 4 + 1 ) = 5

Syntax hints:   = wceq 1284  (class class class)co 5532   1c1 6982   + caddc 6984   4c4 8091   5c5 8092

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-5 1376  ax-gen 1378  ax-ext 2063

This theorem depends on definitions:  df-bi 115  df-cleq 2074  df-5 8101

This theorem is referenced by:  8t7e56  8596  9t6e54  8602  ex-fac  10565