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Mirrors > Home > ILE Home > Th. List > spimh | Unicode version |
Description: Specialization, using implicit substitition. Compare Lemma 14 of [Tarski] p. 70. The spim 1666 series of theorems requires that only one direction of the substitution hypothesis hold. (Contributed by NM, 5-Aug-1993.) (Revised by NM, 8-May-2008.) (New usage is discouraged.) |
Ref | Expression |
---|---|
spimh.1 | |
spimh.2 |
Ref | Expression |
---|---|
spimh |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | spimh.2 | . . . 4 | |
2 | spimh.1 | . . . 4 | |
3 | 1, 2 | syl6com 35 | . . 3 |
4 | 3 | alimi 1384 | . 2 |
5 | ax9o 1628 | . 2 | |
6 | 4, 5 | syl 14 | 1 |
Colors of variables: wff set class |
Syntax hints: wi 4 wal 1282 |
This theorem was proved from axioms: ax-1 5 ax-2 6 ax-mp 7 ax-ia1 104 ax-ia2 105 ax-ia3 106 ax-5 1376 ax-gen 1378 ax-ie1 1422 ax-ie2 1423 ax-4 1440 ax-i9 1463 ax-ial 1467 |
This theorem depends on definitions: df-bi 115 |
This theorem is referenced by: spim 1666 |
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