Theorem hbeud 1963

Description: Deduction version of hbeu 1962. (Contributed by NM, 15-Feb-2013.) (Proof rewritten by Jim Kingdon, 25-May-2018.)

Hypotheses

Ref	Expression
hbeud.1	⊢ (𝜑 → ∀𝑥𝜑)
hbeud.2	⊢ (𝜑 → ∀𝑦𝜑)
hbeud.3	⊢ (𝜑 → (𝜓 → ∀𝑥𝜓))

Assertion

Ref	Expression
hbeud	⊢ (𝜑 → (∃!𝑦𝜓 → ∀𝑥∃!𝑦𝜓))

Proof of Theorem hbeud

Step	Hyp	Ref	Expression
1		hbeud.2	. . . 4 ⊢ (𝜑 → ∀𝑦𝜑)
2	1	nfi 1391	. . 3 ⊢ Ⅎ𝑦𝜑
3		hbeud.1	. . . . 5 ⊢ (𝜑 → ∀𝑥𝜑)
4	3	nfi 1391	. . . 4 ⊢ Ⅎ𝑥𝜑
5		hbeud.3	. . . 4 ⊢ (𝜑 → (𝜓 → ∀𝑥𝜓))
6	4, 5	nfd 1456	. . 3 ⊢ (𝜑 → Ⅎ𝑥𝜓)
7	2, 6	nfeud 1957	. 2 ⊢ (𝜑 → Ⅎ𝑥∃!𝑦𝜓)
8	7	nfrd 1453	1 ⊢ (𝜑 → (∃!𝑦𝜓 → ∀𝑥∃!𝑦𝜓))

Syntax hints:   → wi 4  ∀wal 1282  ∃!weu 1941

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-io 662  ax-5 1376  ax-7 1377  ax-gen 1378  ax-ie1 1422  ax-ie2 1423  ax-8 1435  ax-10 1436  ax-11 1437  ax-i12 1438  ax-bndl 1439  ax-4 1440  ax-17 1459  ax-i9 1463  ax-ial 1467  ax-i5r 1468

This theorem depends on definitions:  df-bi 115  df-tru 1287  df-nf 1390  df-sb 1686  df-eu 1944

This theorem is referenced by: (None)