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Theorem pwssunim 4039
Description: The power class of the union of two classes is a subset of the union of their power classes, if one class is a subclass of the other. One direction of Exercise 4.12(l) of [Mendelson] p. 235. (Contributed by Jim Kingdon, 30-Sep-2018.)
Assertion
Ref Expression
pwssunim ((𝐴𝐵𝐵𝐴) → 𝒫 (𝐴𝐵) ⊆ (𝒫 𝐴 ∪ 𝒫 𝐵))

Proof of Theorem pwssunim
StepHypRef Expression
1 ssequn2 3145 . . . . 5 (𝐵𝐴 ↔ (𝐴𝐵) = 𝐴)
2 pweq 3385 . . . . . 6 ((𝐴𝐵) = 𝐴 → 𝒫 (𝐴𝐵) = 𝒫 𝐴)
3 eqimss 3051 . . . . . 6 (𝒫 (𝐴𝐵) = 𝒫 𝐴 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴)
42, 3syl 14 . . . . 5 ((𝐴𝐵) = 𝐴 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴)
51, 4sylbi 119 . . . 4 (𝐵𝐴 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴)
6 ssequn1 3142 . . . . 5 (𝐴𝐵 ↔ (𝐴𝐵) = 𝐵)
7 pweq 3385 . . . . . 6 ((𝐴𝐵) = 𝐵 → 𝒫 (𝐴𝐵) = 𝒫 𝐵)
8 eqimss 3051 . . . . . 6 (𝒫 (𝐴𝐵) = 𝒫 𝐵 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵)
97, 8syl 14 . . . . 5 ((𝐴𝐵) = 𝐵 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵)
106, 9sylbi 119 . . . 4 (𝐴𝐵 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵)
115, 10orim12i 708 . . 3 ((𝐵𝐴𝐴𝐵) → (𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴 ∨ 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵))
1211orcoms 681 . 2 ((𝐴𝐵𝐵𝐴) → (𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴 ∨ 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵))
13 ssun 3151 . 2 ((𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴 ∨ 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵) → 𝒫 (𝐴𝐵) ⊆ (𝒫 𝐴 ∪ 𝒫 𝐵))
1412, 13syl 14 1 ((𝐴𝐵𝐵𝐴) → 𝒫 (𝐴𝐵) ⊆ (𝒫 𝐴 ∪ 𝒫 𝐵))
Colors of variables: wff set class
Syntax hints:  wi 4  wo 661   = wceq 1284  cun 2971  wss 2973  𝒫 cpw 3382
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-io 662  ax-5 1376  ax-7 1377  ax-gen 1378  ax-ie1 1422  ax-ie2 1423  ax-8 1435  ax-10 1436  ax-11 1437  ax-i12 1438  ax-bndl 1439  ax-4 1440  ax-17 1459  ax-i9 1463  ax-ial 1467  ax-i5r 1468  ax-ext 2063
This theorem depends on definitions:  df-bi 115  df-tru 1287  df-nf 1390  df-sb 1686  df-clab 2068  df-cleq 2074  df-clel 2077  df-nfc 2208  df-v 2603  df-un 2977  df-in 2979  df-ss 2986  df-pw 3384
This theorem is referenced by:  pwunim  4041
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