Theorem 3anibar 1229

Description: Remove a hypothesis from the second member of a biimplication. (Contributed by FL, 22-Jul-2008.)

Hypothesis

Ref	Expression
3anibar.1	|- ( ( ph /\ ps /\ ch ) -> ( th <-> ( ch /\ ta ) ) )

Assertion

Ref	Expression
3anibar	|- ( ( ph /\ ps /\ ch ) -> ( th <-> ta ) )

Proof of Theorem 3anibar

Step	Hyp	Ref	Expression
1		simp3 1063	. 2 |- ( ( ph /\ ps /\ ch ) -> ch )
2		3anibar.1	. 2 |- ( ( ph /\ ps /\ ch ) -> ( th <-> ( ch /\ ta ) ) )
3	1, 2	mpbirand 530	1 |- ( ( ph /\ ps /\ ch ) -> ( th <-> ta ) )

Syntax hints:   -> wi 4   <-> wb 196   /\ wa 384   /\ w3a 1037

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 197  df-an 386  df-3an 1039

This theorem is referenced by:  cpmatel  20516  neiint  20908  islinindfiss  42239