Theorem fvifeq 41299

Description: Equality of function values with conditional arguments, see also fvif 6204. (Contributed by Alexander van der Vekens, 21-May-2018.)

Assertion

Ref	Expression
fvifeq	⊢ (𝐴 = if(𝜑, 𝐵, 𝐶) → (𝐹‘𝐴) = if(𝜑, (𝐹‘𝐵), (𝐹‘𝐶)))

Proof of Theorem fvifeq

Step	Hyp	Ref	Expression
1		fveq2 6191	. 2 ⊢ (𝐴 = if(𝜑, 𝐵, 𝐶) → (𝐹‘𝐴) = (𝐹‘if(𝜑, 𝐵, 𝐶)))
2		fvif 6204	. 2 ⊢ (𝐹‘if(𝜑, 𝐵, 𝐶)) = if(𝜑, (𝐹‘𝐵), (𝐹‘𝐶))
3	1, 2	syl6eq 2672	1 ⊢ (𝐴 = if(𝜑, 𝐵, 𝐶) → (𝐹‘𝐴) = if(𝜑, (𝐹‘𝐵), (𝐹‘𝐶)))

Syntax hints:   → wi 4   = wceq 1483  ifcif 4086  ‘cfv 5888

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-9 1999  ax-10 2019  ax-11 2034  ax-12 2047  ax-13 2246  ax-ext 2602

This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-3an 1039  df-tru 1486  df-ex 1705  df-nf 1710  df-sb 1881  df-clab 2609  df-cleq 2615  df-clel 2618  df-nfc 2753  df-rex 2918  df-rab 2921  df-v 3202  df-dif 3577  df-un 3579  df-in 3581  df-ss 3588  df-nul 3916  df-if 4087  df-sn 4178  df-pr 4180  df-op 4184  df-uni 4437  df-br 4654  df-iota 5851  df-fv 5896

This theorem is referenced by: (None)