Theorem 3mix3 1109

Description: Introduction in triple disjunction. (Contributed by NM, 4-Apr-1995.)

Assertion

Ref	Expression
3mix3	|- ( ph -> ( ps \/ ch \/ ph ) )

Proof of Theorem 3mix3

Step	Hyp	Ref	Expression
1		3mix1 1107	. 2 |- ( ph -> ( ph \/ ps \/ ch ) )
2		3orrot 925	. 2 |- ( ( ph \/ ps \/ ch ) <-> ( ps \/ ch \/ ph ) )
3	1, 2	sylib 120	1 |- ( ph -> ( ps \/ ch \/ ph ) )

Syntax hints:   -> wi 4   \/ w3o 918

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-io 662

This theorem depends on definitions:  df-bi 115  df-3or 920

This theorem is referenced by:  3mix3i  1112  3mix3d  1115  3jaob  1233  tpid3g  3505  funtpg  4970  nn01to3  8702  fztri3or  9058  qbtwnxr  9266