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Theorem 2sb6rf 1907
Description: Reversed double substitution. (Contributed by NM, 3-Feb-2005.)
Hypotheses
Ref Expression
2sb5rf.1 (𝜑 → ∀𝑧𝜑)
2sb5rf.2 (𝜑 → ∀𝑤𝜑)
Assertion
Ref Expression
2sb6rf (𝜑 ↔ ∀𝑧𝑤((𝑧 = 𝑥𝑤 = 𝑦) → [𝑧 / 𝑥][𝑤 / 𝑦]𝜑))
Distinct variable groups:   𝑥,𝑦   𝑥,𝑤   𝑦,𝑧   𝑧,𝑤
Allowed substitution hints:   𝜑(𝑥,𝑦,𝑧,𝑤)

Proof of Theorem 2sb6rf
StepHypRef Expression
1 2sb5rf.1 . . 3 (𝜑 → ∀𝑧𝜑)
21sb6rf 1774 . 2 (𝜑 ↔ ∀𝑧(𝑧 = 𝑥 → [𝑧 / 𝑥]𝜑))
3 19.21v 1794 . . . 4 (∀𝑤(𝑧 = 𝑥 → (𝑤 = 𝑦 → [𝑤 / 𝑦][𝑧 / 𝑥]𝜑)) ↔ (𝑧 = 𝑥 → ∀𝑤(𝑤 = 𝑦 → [𝑤 / 𝑦][𝑧 / 𝑥]𝜑)))
4 sbcom2 1904 . . . . . . 7 ([𝑧 / 𝑥][𝑤 / 𝑦]𝜑 ↔ [𝑤 / 𝑦][𝑧 / 𝑥]𝜑)
54imbi2i 224 . . . . . 6 (((𝑧 = 𝑥𝑤 = 𝑦) → [𝑧 / 𝑥][𝑤 / 𝑦]𝜑) ↔ ((𝑧 = 𝑥𝑤 = 𝑦) → [𝑤 / 𝑦][𝑧 / 𝑥]𝜑))
6 impexp 259 . . . . . 6 (((𝑧 = 𝑥𝑤 = 𝑦) → [𝑤 / 𝑦][𝑧 / 𝑥]𝜑) ↔ (𝑧 = 𝑥 → (𝑤 = 𝑦 → [𝑤 / 𝑦][𝑧 / 𝑥]𝜑)))
75, 6bitri 182 . . . . 5 (((𝑧 = 𝑥𝑤 = 𝑦) → [𝑧 / 𝑥][𝑤 / 𝑦]𝜑) ↔ (𝑧 = 𝑥 → (𝑤 = 𝑦 → [𝑤 / 𝑦][𝑧 / 𝑥]𝜑)))
87albii 1399 . . . 4 (∀𝑤((𝑧 = 𝑥𝑤 = 𝑦) → [𝑧 / 𝑥][𝑤 / 𝑦]𝜑) ↔ ∀𝑤(𝑧 = 𝑥 → (𝑤 = 𝑦 → [𝑤 / 𝑦][𝑧 / 𝑥]𝜑)))
9 2sb5rf.2 . . . . . . 7 (𝜑 → ∀𝑤𝜑)
109hbsbv 1858 . . . . . 6 ([𝑧 / 𝑥]𝜑 → ∀𝑤[𝑧 / 𝑥]𝜑)
1110sb6rf 1774 . . . . 5 ([𝑧 / 𝑥]𝜑 ↔ ∀𝑤(𝑤 = 𝑦 → [𝑤 / 𝑦][𝑧 / 𝑥]𝜑))
1211imbi2i 224 . . . 4 ((𝑧 = 𝑥 → [𝑧 / 𝑥]𝜑) ↔ (𝑧 = 𝑥 → ∀𝑤(𝑤 = 𝑦 → [𝑤 / 𝑦][𝑧 / 𝑥]𝜑)))
133, 8, 123bitr4ri 211 . . 3 ((𝑧 = 𝑥 → [𝑧 / 𝑥]𝜑) ↔ ∀𝑤((𝑧 = 𝑥𝑤 = 𝑦) → [𝑧 / 𝑥][𝑤 / 𝑦]𝜑))
1413albii 1399 . 2 (∀𝑧(𝑧 = 𝑥 → [𝑧 / 𝑥]𝜑) ↔ ∀𝑧𝑤((𝑧 = 𝑥𝑤 = 𝑦) → [𝑧 / 𝑥][𝑤 / 𝑦]𝜑))
152, 14bitri 182 1 (𝜑 ↔ ∀𝑧𝑤((𝑧 = 𝑥𝑤 = 𝑦) → [𝑧 / 𝑥][𝑤 / 𝑦]𝜑))
Colors of variables: wff set class
Syntax hints:  wi 4  wa 102  wb 103  wal 1282  [wsb 1685
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-io 662  ax-5 1376  ax-7 1377  ax-gen 1378  ax-ie1 1422  ax-ie2 1423  ax-8 1435  ax-10 1436  ax-11 1437  ax-i12 1438  ax-4 1440  ax-17 1459  ax-i9 1463  ax-ial 1467  ax-i5r 1468
This theorem depends on definitions:  df-bi 115  df-nf 1390  df-sb 1686
This theorem is referenced by: (None)
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