Theorem abssdv 3068

Description: Deduction of abstraction subclass from implication. (Contributed by NM, 20-Jan-2006.)

Hypothesis

Ref	Expression
abssdv.1	⊢ (𝜑 → (𝜓 → 𝑥 ∈ 𝐴))

Assertion

Ref	Expression
abssdv	⊢ (𝜑 → {𝑥 ∣ 𝜓} ⊆ 𝐴)

Distinct variable groups:   𝜑,𝑥   𝑥,𝐴

Allowed substitution hint:   𝜓(𝑥)

Proof of Theorem abssdv

Step	Hyp	Ref	Expression
1		abssdv.1	. . 3 ⊢ (𝜑 → (𝜓 → 𝑥 ∈ 𝐴))
2	1	alrimiv 1795	. 2 ⊢ (𝜑 → ∀𝑥(𝜓 → 𝑥 ∈ 𝐴))
3		abss 3063	. 2 ⊢ ({𝑥 ∣ 𝜓} ⊆ 𝐴 ↔ ∀𝑥(𝜓 → 𝑥 ∈ 𝐴))
4	2, 3	sylibr 132	1 ⊢ (𝜑 → {𝑥 ∣ 𝜓} ⊆ 𝐴)

Syntax hints:   → wi 4  ∀wal 1282   ∈ wcel 1433  {cab 2067   ⊆ wss 2973

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-io 662  ax-5 1376  ax-7 1377  ax-gen 1378  ax-ie1 1422  ax-ie2 1423  ax-8 1435  ax-10 1436  ax-11 1437  ax-i12 1438  ax-bndl 1439  ax-4 1440  ax-17 1459  ax-i9 1463  ax-ial 1467  ax-i5r 1468  ax-ext 2063

This theorem depends on definitions:  df-bi 115  df-nf 1390  df-sb 1686  df-clab 2068  df-cleq 2074  df-clel 2077  df-nfc 2208  df-in 2979  df-ss 2986

This theorem is referenced by:  fmpt  5340  tfrlemibacc  5963  tfrlemibfn  5965  eroprf  6222  genipv  6699