Theorem abssi 3069

Description: Inference of abstraction subclass from implication. (Contributed by NM, 20-Jan-2006.)

Hypothesis

Ref	Expression
abssi.1	⊢ (𝜑 → 𝑥 ∈ 𝐴)

Assertion

Ref	Expression
abssi	⊢ {𝑥 ∣ 𝜑} ⊆ 𝐴

Distinct variable group:   𝑥,𝐴

Allowed substitution hint:   𝜑(𝑥)

Proof of Theorem abssi

Step	Hyp	Ref	Expression
1		abssi.1	. . 3 ⊢ (𝜑 → 𝑥 ∈ 𝐴)
2	1	ss2abi 3066	. 2 ⊢ {𝑥 ∣ 𝜑} ⊆ {𝑥 ∣ 𝑥 ∈ 𝐴}
3		abid2 2199	. 2 ⊢ {𝑥 ∣ 𝑥 ∈ 𝐴} = 𝐴
4	2, 3	sseqtri 3031	1 ⊢ {𝑥 ∣ 𝜑} ⊆ 𝐴

Syntax hints:   → wi 4   ∈ wcel 1433  {cab 2067   ⊆ wss 2973

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-io 662  ax-5 1376  ax-7 1377  ax-gen 1378  ax-ie1 1422  ax-ie2 1423  ax-8 1435  ax-10 1436  ax-11 1437  ax-i12 1438  ax-bndl 1439  ax-4 1440  ax-17 1459  ax-i9 1463  ax-ial 1467  ax-i5r 1468  ax-ext 2063

This theorem depends on definitions:  df-bi 115  df-nf 1390  df-sb 1686  df-clab 2068  df-cleq 2074  df-clel 2077  df-nfc 2208  df-in 2979  df-ss 2986

This theorem is referenced by:  ssab2  3078  abf  3287  intab  3665  opabss  3842  relopabi  4481  exse2  4719  tfrlem8  5957  frecabex  6007  fiprc  6315  nqprxx  6736  ltnqex  6739  gtnqex  6740  recexprlemell  6812  recexprlemelu  6813  recexprlempr  6822