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Theorem swopolem 4060
Description: Perform the substitutions into the strict weak ordering law. (Contributed by Mario Carneiro, 31-Dec-2014.)
Hypothesis
Ref Expression
swopolem.1 ((𝜑 ∧ (𝑥𝐴𝑦𝐴𝑧𝐴)) → (𝑥𝑅𝑦 → (𝑥𝑅𝑧𝑧𝑅𝑦)))
Assertion
Ref Expression
swopolem ((𝜑 ∧ (𝑋𝐴𝑌𝐴𝑍𝐴)) → (𝑋𝑅𝑌 → (𝑋𝑅𝑍𝑍𝑅𝑌)))
Distinct variable groups:   𝑥,𝑦,𝑧,𝐴   𝜑,𝑥,𝑦,𝑧   𝑥,𝑅,𝑦,𝑧   𝑥,𝑋,𝑦,𝑧   𝑦,𝑌,𝑧   𝑧,𝑍
Allowed substitution hints:   𝑌(𝑥)   𝑍(𝑥,𝑦)

Proof of Theorem swopolem
StepHypRef Expression
1 swopolem.1 . . 3 ((𝜑 ∧ (𝑥𝐴𝑦𝐴𝑧𝐴)) → (𝑥𝑅𝑦 → (𝑥𝑅𝑧𝑧𝑅𝑦)))
21ralrimivvva 2444 . 2 (𝜑 → ∀𝑥𝐴𝑦𝐴𝑧𝐴 (𝑥𝑅𝑦 → (𝑥𝑅𝑧𝑧𝑅𝑦)))
3 breq1 3788 . . . 4 (𝑥 = 𝑋 → (𝑥𝑅𝑦𝑋𝑅𝑦))
4 breq1 3788 . . . . 5 (𝑥 = 𝑋 → (𝑥𝑅𝑧𝑋𝑅𝑧))
54orbi1d 737 . . . 4 (𝑥 = 𝑋 → ((𝑥𝑅𝑧𝑧𝑅𝑦) ↔ (𝑋𝑅𝑧𝑧𝑅𝑦)))
63, 5imbi12d 232 . . 3 (𝑥 = 𝑋 → ((𝑥𝑅𝑦 → (𝑥𝑅𝑧𝑧𝑅𝑦)) ↔ (𝑋𝑅𝑦 → (𝑋𝑅𝑧𝑧𝑅𝑦))))
7 breq2 3789 . . . 4 (𝑦 = 𝑌 → (𝑋𝑅𝑦𝑋𝑅𝑌))
8 breq2 3789 . . . . 5 (𝑦 = 𝑌 → (𝑧𝑅𝑦𝑧𝑅𝑌))
98orbi2d 736 . . . 4 (𝑦 = 𝑌 → ((𝑋𝑅𝑧𝑧𝑅𝑦) ↔ (𝑋𝑅𝑧𝑧𝑅𝑌)))
107, 9imbi12d 232 . . 3 (𝑦 = 𝑌 → ((𝑋𝑅𝑦 → (𝑋𝑅𝑧𝑧𝑅𝑦)) ↔ (𝑋𝑅𝑌 → (𝑋𝑅𝑧𝑧𝑅𝑌))))
11 breq2 3789 . . . . 5 (𝑧 = 𝑍 → (𝑋𝑅𝑧𝑋𝑅𝑍))
12 breq1 3788 . . . . 5 (𝑧 = 𝑍 → (𝑧𝑅𝑌𝑍𝑅𝑌))
1311, 12orbi12d 739 . . . 4 (𝑧 = 𝑍 → ((𝑋𝑅𝑧𝑧𝑅𝑌) ↔ (𝑋𝑅𝑍𝑍𝑅𝑌)))
1413imbi2d 228 . . 3 (𝑧 = 𝑍 → ((𝑋𝑅𝑌 → (𝑋𝑅𝑧𝑧𝑅𝑌)) ↔ (𝑋𝑅𝑌 → (𝑋𝑅𝑍𝑍𝑅𝑌))))
156, 10, 14rspc3v 2716 . 2 ((𝑋𝐴𝑌𝐴𝑍𝐴) → (∀𝑥𝐴𝑦𝐴𝑧𝐴 (𝑥𝑅𝑦 → (𝑥𝑅𝑧𝑧𝑅𝑦)) → (𝑋𝑅𝑌 → (𝑋𝑅𝑍𝑍𝑅𝑌))))
162, 15mpan9 275 1 ((𝜑 ∧ (𝑋𝐴𝑌𝐴𝑍𝐴)) → (𝑋𝑅𝑌 → (𝑋𝑅𝑍𝑍𝑅𝑌)))
Colors of variables: wff set class
Syntax hints:  wi 4  wa 102  wo 661  w3a 919   = wceq 1284  wcel 1433  wral 2348   class class class wbr 3785
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-io 662  ax-5 1376  ax-7 1377  ax-gen 1378  ax-ie1 1422  ax-ie2 1423  ax-8 1435  ax-10 1436  ax-11 1437  ax-i12 1438  ax-bndl 1439  ax-4 1440  ax-17 1459  ax-i9 1463  ax-ial 1467  ax-i5r 1468  ax-ext 2063
This theorem depends on definitions:  df-bi 115  df-3an 921  df-tru 1287  df-nf 1390  df-sb 1686  df-clab 2068  df-cleq 2074  df-clel 2077  df-nfc 2208  df-ral 2353  df-v 2603  df-un 2977  df-sn 3404  df-pr 3405  df-op 3407  df-br 3786
This theorem is referenced by:  swoer  6157  swoord1  6158  swoord2  6159
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