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Theorem undifss 3323
Description: Union of complementary parts into whole. (Contributed by Jim Kingdon, 4-Aug-2018.)
Assertion
Ref Expression
undifss (𝐴𝐵 ↔ (𝐴 ∪ (𝐵𝐴)) ⊆ 𝐵)

Proof of Theorem undifss
StepHypRef Expression
1 difss 3098 . . . 4 (𝐵𝐴) ⊆ 𝐵
21jctr 308 . . 3 (𝐴𝐵 → (𝐴𝐵 ∧ (𝐵𝐴) ⊆ 𝐵))
3 unss 3146 . . 3 ((𝐴𝐵 ∧ (𝐵𝐴) ⊆ 𝐵) ↔ (𝐴 ∪ (𝐵𝐴)) ⊆ 𝐵)
42, 3sylib 120 . 2 (𝐴𝐵 → (𝐴 ∪ (𝐵𝐴)) ⊆ 𝐵)
5 ssun1 3135 . . 3 𝐴 ⊆ (𝐴 ∪ (𝐵𝐴))
6 sstr 3007 . . 3 ((𝐴 ⊆ (𝐴 ∪ (𝐵𝐴)) ∧ (𝐴 ∪ (𝐵𝐴)) ⊆ 𝐵) → 𝐴𝐵)
75, 6mpan 414 . 2 ((𝐴 ∪ (𝐵𝐴)) ⊆ 𝐵𝐴𝐵)
84, 7impbii 124 1 (𝐴𝐵 ↔ (𝐴 ∪ (𝐵𝐴)) ⊆ 𝐵)
Colors of variables: wff set class
Syntax hints:  wa 102  wb 103  cdif 2970  cun 2971  wss 2973
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-in1 576  ax-in2 577  ax-io 662  ax-5 1376  ax-7 1377  ax-gen 1378  ax-ie1 1422  ax-ie2 1423  ax-8 1435  ax-10 1436  ax-11 1437  ax-i12 1438  ax-bndl 1439  ax-4 1440  ax-17 1459  ax-i9 1463  ax-ial 1467  ax-i5r 1468  ax-ext 2063
This theorem depends on definitions:  df-bi 115  df-tru 1287  df-nf 1390  df-sb 1686  df-clab 2068  df-cleq 2074  df-clel 2077  df-nfc 2208  df-v 2603  df-dif 2975  df-un 2977  df-in 2979  df-ss 2986
This theorem is referenced by:  difsnss  3531
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