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Theorem bi2bian9 919
Description: Deduction joining two biconditionals with different antecedents. (Contributed by NM, 12-May-2004.)
Hypotheses
Ref Expression
bi2an9.1  |-  ( ph  ->  ( ps  <->  ch )
)
bi2an9.2  |-  ( th 
->  ( ta  <->  et )
)
Assertion
Ref Expression
bi2bian9  |-  ( (
ph  /\  th )  ->  ( ( ps  <->  ta )  <->  ( ch  <->  et ) ) )

Proof of Theorem bi2bian9
StepHypRef Expression
1 bi2an9.1 . . 3  |-  ( ph  ->  ( ps  <->  ch )
)
21adantr 481 . 2  |-  ( (
ph  /\  th )  ->  ( ps  <->  ch )
)
3 bi2an9.2 . . 3  |-  ( th 
->  ( ta  <->  et )
)
43adantl 482 . 2  |-  ( (
ph  /\  th )  ->  ( ta  <->  et )
)
52, 4bibi12d 335 1  |-  ( (
ph  /\  th )  ->  ( ( ps  <->  ta )  <->  ( ch  <->  et ) ) )
Colors of variables: wff setvar class
Syntax hints:    -> wi 4    <-> wb 196    /\ wa 384
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 197  df-an 386
This theorem is referenced by:  releccnveq  34022  wepwsolem  37612  aomclem8  37631
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