Users' Mathboxes Mathbox for Steve Rodriguez < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >   Mathboxes  >  ssrecnpr Structured version   Visualization version   Unicode version

Theorem ssrecnpr 38507
Description:  RR is a subset of both  RR and  CC. (Contributed by Steve Rodriguez, 22-Nov-2015.)
Assertion
Ref Expression
ssrecnpr  |-  ( S  e.  { RR ,  CC }  ->  RR  C_  S
)

Proof of Theorem ssrecnpr
StepHypRef Expression
1 elpri 4197 . 2  |-  ( S  e.  { RR ,  CC }  ->  ( S  =  RR  \/  S  =  CC ) )
2 eqimss2 3658 . . 3  |-  ( S  =  RR  ->  RR  C_  S )
3 ax-resscn 9993 . . . 4  |-  RR  C_  CC
4 sseq2 3627 . . . 4  |-  ( S  =  CC  ->  ( RR  C_  S  <->  RR  C_  CC ) )
53, 4mpbiri 248 . . 3  |-  ( S  =  CC  ->  RR  C_  S )
62, 5jaoi 394 . 2  |-  ( ( S  =  RR  \/  S  =  CC )  ->  RR  C_  S )
71, 6syl 17 1  |-  ( S  e.  { RR ,  CC }  ->  RR  C_  S
)
Colors of variables: wff setvar class
Syntax hints:    -> wi 4    \/ wo 383    = wceq 1483    e. wcel 1990    C_ wss 3574   {cpr 4179   CCcc 9934   RRcr 9935
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-9 1999  ax-10 2019  ax-11 2034  ax-12 2047  ax-13 2246  ax-ext 2602  ax-resscn 9993
This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-tru 1486  df-ex 1705  df-nf 1710  df-sb 1881  df-clab 2609  df-cleq 2615  df-clel 2618  df-nfc 2753  df-v 3202  df-un 3579  df-in 3581  df-ss 3588  df-sn 4178  df-pr 4180
This theorem is referenced by: (None)
  Copyright terms: Public domain W3C validator