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Mirrors > Home > MPE Home > Th. List > efgcpbllema | Structured version Visualization version GIF version |
Description: Lemma for efgrelex 18164. Define an auxiliary equivalence relation 𝐿 such that 𝐴𝐿𝐵 if there are sequences from 𝐴 to 𝐵 passing through the same reduced word. (Contributed by Mario Carneiro, 1-Oct-2015.) |
Ref | Expression |
---|---|
efgval.w | ⊢ 𝑊 = ( I ‘Word (𝐼 × 2𝑜)) |
efgval.r | ⊢ ∼ = ( ~FG ‘𝐼) |
efgval2.m | ⊢ 𝑀 = (𝑦 ∈ 𝐼, 𝑧 ∈ 2𝑜 ↦ 〈𝑦, (1𝑜 ∖ 𝑧)〉) |
efgval2.t | ⊢ 𝑇 = (𝑣 ∈ 𝑊 ↦ (𝑛 ∈ (0...(#‘𝑣)), 𝑤 ∈ (𝐼 × 2𝑜) ↦ (𝑣 splice 〈𝑛, 𝑛, 〈“𝑤(𝑀‘𝑤)”〉〉))) |
efgred.d | ⊢ 𝐷 = (𝑊 ∖ ∪ 𝑥 ∈ 𝑊 ran (𝑇‘𝑥)) |
efgred.s | ⊢ 𝑆 = (𝑚 ∈ {𝑡 ∈ (Word 𝑊 ∖ {∅}) ∣ ((𝑡‘0) ∈ 𝐷 ∧ ∀𝑘 ∈ (1..^(#‘𝑡))(𝑡‘𝑘) ∈ ran (𝑇‘(𝑡‘(𝑘 − 1))))} ↦ (𝑚‘((#‘𝑚) − 1))) |
efgcpbllem.1 | ⊢ 𝐿 = {〈𝑖, 𝑗〉 ∣ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵))} |
Ref | Expression |
---|---|
efgcpbllema | ⊢ (𝑋𝐿𝑌 ↔ (𝑋 ∈ 𝑊 ∧ 𝑌 ∈ 𝑊 ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ∼ ((𝐴 ++ 𝑌) ++ 𝐵))) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | oveq2 6658 | . . . . 5 ⊢ (𝑖 = 𝑋 → (𝐴 ++ 𝑖) = (𝐴 ++ 𝑋)) | |
2 | 1 | oveq1d 6665 | . . . 4 ⊢ (𝑖 = 𝑋 → ((𝐴 ++ 𝑖) ++ 𝐵) = ((𝐴 ++ 𝑋) ++ 𝐵)) |
3 | oveq2 6658 | . . . . 5 ⊢ (𝑗 = 𝑌 → (𝐴 ++ 𝑗) = (𝐴 ++ 𝑌)) | |
4 | 3 | oveq1d 6665 | . . . 4 ⊢ (𝑗 = 𝑌 → ((𝐴 ++ 𝑗) ++ 𝐵) = ((𝐴 ++ 𝑌) ++ 𝐵)) |
5 | 2, 4 | breqan12d 4669 | . . 3 ⊢ ((𝑖 = 𝑋 ∧ 𝑗 = 𝑌) → (((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵) ↔ ((𝐴 ++ 𝑋) ++ 𝐵) ∼ ((𝐴 ++ 𝑌) ++ 𝐵))) |
6 | efgcpbllem.1 | . . . 4 ⊢ 𝐿 = {〈𝑖, 𝑗〉 ∣ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵))} | |
7 | vex 3203 | . . . . . . 7 ⊢ 𝑖 ∈ V | |
8 | vex 3203 | . . . . . . 7 ⊢ 𝑗 ∈ V | |
9 | 7, 8 | prss 4351 | . . . . . 6 ⊢ ((𝑖 ∈ 𝑊 ∧ 𝑗 ∈ 𝑊) ↔ {𝑖, 𝑗} ⊆ 𝑊) |
10 | 9 | anbi1i 731 | . . . . 5 ⊢ (((𝑖 ∈ 𝑊 ∧ 𝑗 ∈ 𝑊) ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵)) ↔ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵))) |
11 | 10 | opabbii 4717 | . . . 4 ⊢ {〈𝑖, 𝑗〉 ∣ ((𝑖 ∈ 𝑊 ∧ 𝑗 ∈ 𝑊) ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵))} = {〈𝑖, 𝑗〉 ∣ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵))} |
12 | 6, 11 | eqtr4i 2647 | . . 3 ⊢ 𝐿 = {〈𝑖, 𝑗〉 ∣ ((𝑖 ∈ 𝑊 ∧ 𝑗 ∈ 𝑊) ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵))} |
13 | 5, 12 | brab2a 5194 | . 2 ⊢ (𝑋𝐿𝑌 ↔ ((𝑋 ∈ 𝑊 ∧ 𝑌 ∈ 𝑊) ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ∼ ((𝐴 ++ 𝑌) ++ 𝐵))) |
14 | df-3an 1039 | . 2 ⊢ ((𝑋 ∈ 𝑊 ∧ 𝑌 ∈ 𝑊 ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ∼ ((𝐴 ++ 𝑌) ++ 𝐵)) ↔ ((𝑋 ∈ 𝑊 ∧ 𝑌 ∈ 𝑊) ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ∼ ((𝐴 ++ 𝑌) ++ 𝐵))) | |
15 | 13, 14 | bitr4i 267 | 1 ⊢ (𝑋𝐿𝑌 ↔ (𝑋 ∈ 𝑊 ∧ 𝑌 ∈ 𝑊 ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ∼ ((𝐴 ++ 𝑌) ++ 𝐵))) |
Colors of variables: wff setvar class |
Syntax hints: ↔ wb 196 ∧ wa 384 ∧ w3a 1037 = wceq 1483 ∈ wcel 1990 ∀wral 2912 {crab 2916 ∖ cdif 3571 ⊆ wss 3574 ∅c0 3915 {csn 4177 {cpr 4179 〈cop 4183 〈cotp 4185 ∪ ciun 4520 class class class wbr 4653 {copab 4712 ↦ cmpt 4729 I cid 5023 × cxp 5112 ran crn 5115 ‘cfv 5888 (class class class)co 6650 ↦ cmpt2 6652 1𝑜c1o 7553 2𝑜c2o 7554 0cc0 9936 1c1 9937 − cmin 10266 ...cfz 12326 ..^cfzo 12465 #chash 13117 Word cword 13291 ++ cconcat 13293 splice csplice 13296 〈“cs2 13586 ~FG cefg 18119 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1722 ax-4 1737 ax-5 1839 ax-6 1888 ax-7 1935 ax-9 1999 ax-10 2019 ax-11 2034 ax-12 2047 ax-13 2246 ax-ext 2602 ax-sep 4781 ax-nul 4789 ax-pr 4906 |
This theorem depends on definitions: df-bi 197 df-or 385 df-an 386 df-3an 1039 df-tru 1486 df-ex 1705 df-nf 1710 df-sb 1881 df-eu 2474 df-mo 2475 df-clab 2609 df-cleq 2615 df-clel 2618 df-nfc 2753 df-ral 2917 df-rex 2918 df-rab 2921 df-v 3202 df-dif 3577 df-un 3579 df-in 3581 df-ss 3588 df-nul 3916 df-if 4087 df-sn 4178 df-pr 4180 df-op 4184 df-uni 4437 df-br 4654 df-opab 4713 df-xp 5120 df-iota 5851 df-fv 5896 df-ov 6653 |
This theorem is referenced by: efgcpbllemb 18168 efgcpbl 18169 |
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