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Theorem elcnvintab 37908
Description: Two ways of saying a set is an element of the converse of the intersection of a class. (Contributed by RP, 19-Aug-2020.)
Assertion
Ref Expression
elcnvintab (𝐴 {𝑥𝜑} ↔ (𝐴 ∈ (V × V) ∧ ∀𝑥(𝜑𝐴𝑥)))
Distinct variable group:   𝑥,𝐴
Allowed substitution hint:   𝜑(𝑥)

Proof of Theorem elcnvintab
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 eqid 2622 . . 3 (𝑦 ∈ (V × V) ↦ ⟨(2nd𝑦), (1st𝑦)⟩) = (𝑦 ∈ (V × V) ↦ ⟨(2nd𝑦), (1st𝑦)⟩)
21elcnvlem 37907 . 2 (𝐴 {𝑥𝜑} ↔ (𝐴 ∈ (V × V) ∧ ((𝑦 ∈ (V × V) ↦ ⟨(2nd𝑦), (1st𝑦)⟩)‘𝐴) ∈ {𝑥𝜑}))
31elcnvlem 37907 . 2 (𝐴𝑥 ↔ (𝐴 ∈ (V × V) ∧ ((𝑦 ∈ (V × V) ↦ ⟨(2nd𝑦), (1st𝑦)⟩)‘𝐴) ∈ 𝑥))
42, 3elmapintab 37902 1 (𝐴 {𝑥𝜑} ↔ (𝐴 ∈ (V × V) ∧ ∀𝑥(𝜑𝐴𝑥)))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 196  wa 384  wal 1481  wcel 1990  {cab 2608  Vcvv 3200  cop 4183   cint 4475  cmpt 4729   × cxp 5112  ccnv 5113  cfv 5888  1st c1st 7166  2nd c2nd 7167
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-8 1992  ax-9 1999  ax-10 2019  ax-11 2034  ax-12 2047  ax-13 2246  ax-ext 2602  ax-sep 4781  ax-nul 4789  ax-pow 4843  ax-pr 4906  ax-un 6949
This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-3an 1039  df-tru 1486  df-ex 1705  df-nf 1710  df-sb 1881  df-eu 2474  df-mo 2475  df-clab 2609  df-cleq 2615  df-clel 2618  df-nfc 2753  df-ral 2917  df-rex 2918  df-rab 2921  df-v 3202  df-sbc 3436  df-dif 3577  df-un 3579  df-in 3581  df-ss 3588  df-nul 3916  df-if 4087  df-sn 4178  df-pr 4180  df-op 4184  df-uni 4437  df-int 4476  df-br 4654  df-opab 4713  df-mpt 4730  df-id 5024  df-xp 5120  df-rel 5121  df-cnv 5122  df-co 5123  df-dm 5124  df-rn 5125  df-iota 5851  df-fun 5890  df-fv 5896  df-1st 7168  df-2nd 7169
This theorem is referenced by:  cnvintabd  37909
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