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Theorem rabrab 29338
Description: Abstract builder restricted to another restricted abstract builder. (Contributed by Thierry Arnoux, 30-Aug-2017.)
Assertion
Ref Expression
rabrab {𝑥 ∈ {𝑥𝐴𝜑} ∣ 𝜓} = {𝑥𝐴 ∣ (𝜑𝜓)}

Proof of Theorem rabrab
StepHypRef Expression
1 rabid 3116 . . . . 5 (𝑥 ∈ {𝑥𝐴𝜑} ↔ (𝑥𝐴𝜑))
21anbi1i 731 . . . 4 ((𝑥 ∈ {𝑥𝐴𝜑} ∧ 𝜓) ↔ ((𝑥𝐴𝜑) ∧ 𝜓))
3 anass 681 . . . 4 (((𝑥𝐴𝜑) ∧ 𝜓) ↔ (𝑥𝐴 ∧ (𝜑𝜓)))
42, 3bitri 264 . . 3 ((𝑥 ∈ {𝑥𝐴𝜑} ∧ 𝜓) ↔ (𝑥𝐴 ∧ (𝜑𝜓)))
54abbii 2739 . 2 {𝑥 ∣ (𝑥 ∈ {𝑥𝐴𝜑} ∧ 𝜓)} = {𝑥 ∣ (𝑥𝐴 ∧ (𝜑𝜓))}
6 df-rab 2921 . 2 {𝑥 ∈ {𝑥𝐴𝜑} ∣ 𝜓} = {𝑥 ∣ (𝑥 ∈ {𝑥𝐴𝜑} ∧ 𝜓)}
7 df-rab 2921 . 2 {𝑥𝐴 ∣ (𝜑𝜓)} = {𝑥 ∣ (𝑥𝐴 ∧ (𝜑𝜓))}
85, 6, 73eqtr4i 2654 1 {𝑥 ∈ {𝑥𝐴𝜑} ∣ 𝜓} = {𝑥𝐴 ∣ (𝜑𝜓)}
Colors of variables: wff setvar class
Syntax hints:  wa 384   = wceq 1483  wcel 1990  {cab 2608  {crab 2916
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-9 1999  ax-10 2019  ax-11 2034  ax-12 2047  ax-13 2246  ax-ext 2602
This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-tru 1486  df-ex 1705  df-nf 1710  df-sb 1881  df-clab 2609  df-cleq 2615  df-clel 2618  df-rab 2921
This theorem is referenced by:  fpwrelmapffs  29509
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