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Theorem sbeqalb 3488
Description: Theorem *14.121 in [WhiteheadRussell] p. 185. (Contributed by Andrew Salmon, 28-Jun-2011.) (Proof shortened by Wolf Lammen, 9-May-2013.)
Assertion
Ref Expression
sbeqalb (𝐴𝑉 → ((∀𝑥(𝜑𝑥 = 𝐴) ∧ ∀𝑥(𝜑𝑥 = 𝐵)) → 𝐴 = 𝐵))
Distinct variable groups:   𝑥,𝐴   𝑥,𝐵
Allowed substitution hints:   𝜑(𝑥)   𝑉(𝑥)

Proof of Theorem sbeqalb
StepHypRef Expression
1 bibi1 341 . . . . 5 ((𝜑𝑥 = 𝐴) → ((𝜑𝑥 = 𝐵) ↔ (𝑥 = 𝐴𝑥 = 𝐵)))
21biimpa 501 . . . 4 (((𝜑𝑥 = 𝐴) ∧ (𝜑𝑥 = 𝐵)) → (𝑥 = 𝐴𝑥 = 𝐵))
32biimpd 219 . . 3 (((𝜑𝑥 = 𝐴) ∧ (𝜑𝑥 = 𝐵)) → (𝑥 = 𝐴𝑥 = 𝐵))
43alanimi 1744 . 2 ((∀𝑥(𝜑𝑥 = 𝐴) ∧ ∀𝑥(𝜑𝑥 = 𝐵)) → ∀𝑥(𝑥 = 𝐴𝑥 = 𝐵))
5 sbceqal 3487 . 2 (𝐴𝑉 → (∀𝑥(𝑥 = 𝐴𝑥 = 𝐵) → 𝐴 = 𝐵))
64, 5syl5 34 1 (𝐴𝑉 → ((∀𝑥(𝜑𝑥 = 𝐴) ∧ ∀𝑥(𝜑𝑥 = 𝐵)) → 𝐴 = 𝐵))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 196  wa 384  wal 1481   = wceq 1483  wcel 1990
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-9 1999  ax-10 2019  ax-11 2034  ax-12 2047  ax-13 2246  ax-ext 2602
This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-tru 1486  df-ex 1705  df-nf 1710  df-sb 1881  df-clab 2609  df-cleq 2615  df-clel 2618  df-v 3202  df-sbc 3436
This theorem is referenced by:  iotaval  5862
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