Theorem wl-equsb3 33337

Description: equsb3 2432 with a distinctor. (Contributed by Wolf Lammen, 27-Jun-2019.)

Assertion

Ref	Expression
wl-equsb3	⊢ (¬ ∀𝑦 𝑦 = 𝑧 → ([𝑥 / 𝑦]𝑦 = 𝑧 ↔ 𝑥 = 𝑧))

Proof of Theorem wl-equsb3

Dummy variable 𝑤 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		nfv 1843	. . 3 ⊢ Ⅎ𝑤 ¬ ∀𝑦 𝑦 = 𝑧
2		nfna1 2029	. . . 4 ⊢ Ⅎ𝑦 ¬ ∀𝑦 𝑦 = 𝑧
3		nfeqf2 2297	. . . 4 ⊢ (¬ ∀𝑦 𝑦 = 𝑧 → Ⅎ𝑦 𝑤 = 𝑧)
4		equequ1 1952	. . . . 5 ⊢ (𝑦 = 𝑤 → (𝑦 = 𝑧 ↔ 𝑤 = 𝑧))
5	4	a1i 11	. . . 4 ⊢ (¬ ∀𝑦 𝑦 = 𝑧 → (𝑦 = 𝑤 → (𝑦 = 𝑧 ↔ 𝑤 = 𝑧)))
6	2, 3, 5	sbied 2409	. . 3 ⊢ (¬ ∀𝑦 𝑦 = 𝑧 → ([𝑤 / 𝑦]𝑦 = 𝑧 ↔ 𝑤 = 𝑧))
7	1, 6	sbbid 2403	. 2 ⊢ (¬ ∀𝑦 𝑦 = 𝑧 → ([𝑥 / 𝑤][𝑤 / 𝑦]𝑦 = 𝑧 ↔ [𝑥 / 𝑤]𝑤 = 𝑧))
8		sbcom3 2411	. . 3 ⊢ ([𝑥 / 𝑤][𝑤 / 𝑦]𝑦 = 𝑧 ↔ [𝑥 / 𝑤][𝑥 / 𝑦]𝑦 = 𝑧)
9		nfv 1843	. . . 4 ⊢ Ⅎ𝑤[𝑥 / 𝑦]𝑦 = 𝑧
10	9	sbf 2380	. . 3 ⊢ ([𝑥 / 𝑤][𝑥 / 𝑦]𝑦 = 𝑧 ↔ [𝑥 / 𝑦]𝑦 = 𝑧)
11	8, 10	bitri 264	. 2 ⊢ ([𝑥 / 𝑤][𝑤 / 𝑦]𝑦 = 𝑧 ↔ [𝑥 / 𝑦]𝑦 = 𝑧)
12		equsb3 2432	. 2 ⊢ ([𝑥 / 𝑤]𝑤 = 𝑧 ↔ 𝑥 = 𝑧)
13	7, 11, 12	3bitr3g 302	1 ⊢ (¬ ∀𝑦 𝑦 = 𝑧 → ([𝑥 / 𝑦]𝑦 = 𝑧 ↔ 𝑥 = 𝑧))

Syntax hints:  ¬ wn 3   → wi 4   ↔ wb 196  ∀wal 1481  [wsb 1880

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-10 2019  ax-12 2047  ax-13 2246

This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-ex 1705  df-nf 1710  df-sb 1881

This theorem is referenced by: (None)