Theorem spsbim 1764

Description: Specialization of implication. (Contributed by NM, 5-Aug-1993.) (Proof rewritten by Jim Kingdon, 21-Jan-2018.)

Assertion

Ref	Expression
spsbim	|- ( A. x ( ph -> ps ) -> ( [ y / x ] ph -> [ y / x ] ps ) )

Proof of Theorem spsbim

Step	Hyp	Ref	Expression
1		imim2 54	. . . 4 |- ( ( ph -> ps ) -> ( ( x = y -> ph ) -> ( x = y -> ps ) ) )
2	1	sps 1470	. . 3 |- ( A. x ( ph -> ps ) -> ( ( x = y -> ph ) -> ( x = y -> ps ) ) )
3		id 19	. . . . . 6 |- ( ( ph -> ps ) -> ( ph -> ps ) )
4	3	anim2d 330	. . . . 5 |- ( ( ph -> ps ) -> ( ( x = y /\ ph ) -> ( x = y /\ ps ) ) )
5	4	alimi 1384	. . . 4 |- ( A. x ( ph -> ps ) -> A. x ( ( x = y /\ ph ) -> ( x = y /\ ps ) ) )
6		exim 1530	. . . 4 |- ( A. x ( ( x = y /\ ph ) -> ( x = y /\ ps ) ) -> ( E. x ( x = y /\ ph ) -> E. x ( x = y /\ ps ) ) )
7	5, 6	syl 14	. . 3 |- ( A. x ( ph -> ps ) -> ( E. x ( x = y /\ ph ) -> E. x ( x = y /\ ps ) ) )
8	2, 7	anim12d 328	. 2 |- ( A. x ( ph -> ps ) -> ( ( ( x = y -> ph ) /\ E. x ( x = y /\ ph ) ) -> ( ( x = y -> ps ) /\ E. x ( x = y /\ ps ) ) ) )
9		df-sb 1686	. 2 |- ( [ y / x ] ph <-> ( ( x = y -> ph ) /\ E. x ( x = y /\ ph ) ) )
10		df-sb 1686	. 2 |- ( [ y / x ] ps <-> ( ( x = y -> ps ) /\ E. x ( x = y /\ ps ) ) )
11	8, 9, 10	3imtr4g 203	1 |- ( A. x ( ph -> ps ) -> ( [ y / x ] ph -> [ y / x ] ps ) )

Syntax hints:   -> wi 4   /\ wa 102   A.wal 1282   E.wex 1421   [wsb 1685

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-5 1376  ax-gen 1378  ax-ie1 1422  ax-ie2 1423  ax-4 1440  ax-ial 1467

This theorem depends on definitions:  df-bi 115  df-sb 1686

This theorem is referenced by:  spsbbi  1765  hbsb4t  1930  moim  2005