Theorem sbal1yz 1918

Description: Lemma for proving sbal1 1919. Same as sbal1 1919 but with an additional distinct variable constraint on 𝑦 and 𝑧. (Contributed by Jim Kingdon, 23-Feb-2018.)

Assertion

Ref	Expression
sbal1yz	⊢ (¬ ∀𝑥 𝑥 = 𝑧 → ([𝑧 / 𝑦]∀𝑥𝜑 ↔ ∀𝑥[𝑧 / 𝑦]𝜑))

Distinct variable groups:   𝑥,𝑦   𝑦,𝑧

Allowed substitution hints:   𝜑(𝑥,𝑦,𝑧)

Proof of Theorem sbal1yz

Step	Hyp	Ref	Expression
1		dveeq2or 1737	. . . . . 6 ⊢ (∀𝑥 𝑥 = 𝑧 ∨ Ⅎ𝑥 𝑦 = 𝑧)
2		equcom 1633	. . . . . . . . 9 ⊢ (𝑦 = 𝑧 ↔ 𝑧 = 𝑦)
3	2	nfbii 1402	. . . . . . . 8 ⊢ (Ⅎ𝑥 𝑦 = 𝑧 ↔ Ⅎ𝑥 𝑧 = 𝑦)
4		19.21t 1514	. . . . . . . 8 ⊢ (Ⅎ𝑥 𝑧 = 𝑦 → (∀𝑥(𝑧 = 𝑦 → 𝜑) ↔ (𝑧 = 𝑦 → ∀𝑥𝜑)))
5	3, 4	sylbi 119	. . . . . . 7 ⊢ (Ⅎ𝑥 𝑦 = 𝑧 → (∀𝑥(𝑧 = 𝑦 → 𝜑) ↔ (𝑧 = 𝑦 → ∀𝑥𝜑)))
6	5	orim2i 710	. . . . . 6 ⊢ ((∀𝑥 𝑥 = 𝑧 ∨ Ⅎ𝑥 𝑦 = 𝑧) → (∀𝑥 𝑥 = 𝑧 ∨ (∀𝑥(𝑧 = 𝑦 → 𝜑) ↔ (𝑧 = 𝑦 → ∀𝑥𝜑))))
7	1, 6	ax-mp 7	. . . . 5 ⊢ (∀𝑥 𝑥 = 𝑧 ∨ (∀𝑥(𝑧 = 𝑦 → 𝜑) ↔ (𝑧 = 𝑦 → ∀𝑥𝜑)))
8	7	ori 674	. . . 4 ⊢ (¬ ∀𝑥 𝑥 = 𝑧 → (∀𝑥(𝑧 = 𝑦 → 𝜑) ↔ (𝑧 = 𝑦 → ∀𝑥𝜑)))
9	8	albidv 1745	. . 3 ⊢ (¬ ∀𝑥 𝑥 = 𝑧 → (∀𝑦∀𝑥(𝑧 = 𝑦 → 𝜑) ↔ ∀𝑦(𝑧 = 𝑦 → ∀𝑥𝜑)))
10		alcom 1407	. . . 4 ⊢ (∀𝑦∀𝑥(𝑧 = 𝑦 → 𝜑) ↔ ∀𝑥∀𝑦(𝑧 = 𝑦 → 𝜑))
11		sb6 1807	. . . . . 6 ⊢ ([𝑧 / 𝑦]𝜑 ↔ ∀𝑦(𝑦 = 𝑧 → 𝜑))
12	2	imbi1i 236	. . . . . . 7 ⊢ ((𝑦 = 𝑧 → 𝜑) ↔ (𝑧 = 𝑦 → 𝜑))
13	12	albii 1399	. . . . . 6 ⊢ (∀𝑦(𝑦 = 𝑧 → 𝜑) ↔ ∀𝑦(𝑧 = 𝑦 → 𝜑))
14	11, 13	bitri 182	. . . . 5 ⊢ ([𝑧 / 𝑦]𝜑 ↔ ∀𝑦(𝑧 = 𝑦 → 𝜑))
15	14	albii 1399	. . . 4 ⊢ (∀𝑥[𝑧 / 𝑦]𝜑 ↔ ∀𝑥∀𝑦(𝑧 = 𝑦 → 𝜑))
16	10, 15	bitr4i 185	. . 3 ⊢ (∀𝑦∀𝑥(𝑧 = 𝑦 → 𝜑) ↔ ∀𝑥[𝑧 / 𝑦]𝜑)
17		sb6 1807	. . . 4 ⊢ ([𝑧 / 𝑦]∀𝑥𝜑 ↔ ∀𝑦(𝑦 = 𝑧 → ∀𝑥𝜑))
18	2	imbi1i 236	. . . . 5 ⊢ ((𝑦 = 𝑧 → ∀𝑥𝜑) ↔ (𝑧 = 𝑦 → ∀𝑥𝜑))
19	18	albii 1399	. . . 4 ⊢ (∀𝑦(𝑦 = 𝑧 → ∀𝑥𝜑) ↔ ∀𝑦(𝑧 = 𝑦 → ∀𝑥𝜑))
20	17, 19	bitr2i 183	. . 3 ⊢ (∀𝑦(𝑧 = 𝑦 → ∀𝑥𝜑) ↔ [𝑧 / 𝑦]∀𝑥𝜑)
21	9, 16, 20	3bitr3g 220	. 2 ⊢ (¬ ∀𝑥 𝑥 = 𝑧 → (∀𝑥[𝑧 / 𝑦]𝜑 ↔ [𝑧 / 𝑦]∀𝑥𝜑))
22	21	bicomd 139	1 ⊢ (¬ ∀𝑥 𝑥 = 𝑧 → ([𝑧 / 𝑦]∀𝑥𝜑 ↔ ∀𝑥[𝑧 / 𝑦]𝜑))

Syntax hints:  ¬ wn 3   → wi 4   ↔ wb 103   ∨ wo 661  ∀wal 1282  Ⅎwnf 1389  [wsb 1685

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-in2 577  ax-io 662  ax-5 1376  ax-7 1377  ax-gen 1378  ax-ie1 1422  ax-ie2 1423  ax-8 1435  ax-10 1436  ax-11 1437  ax-i12 1438  ax-4 1440  ax-17 1459  ax-i9 1463  ax-ial 1467  ax-i5r 1468

This theorem depends on definitions:  df-bi 115  df-nf 1390  df-sb 1686

This theorem is referenced by:  sbal1  1919