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Mirrors > Home > ILE Home > Th. List > spim | GIF version |
Description: Specialization, using implicit substitution. Compare Lemma 14 of [Tarski] p. 70. The spim 1666 series of theorems requires that only one direction of the substitution hypothesis hold. (Contributed by NM, 5-Aug-1993.) (Revised by Mario Carneiro, 3-Oct-2016.) (Proof rewritten by Jim Kingdon, 10-Jun-2018.) |
Ref | Expression |
---|---|
spim.1 | ⊢ Ⅎ𝑥𝜓 |
spim.2 | ⊢ (𝑥 = 𝑦 → (𝜑 → 𝜓)) |
Ref | Expression |
---|---|
spim | ⊢ (∀𝑥𝜑 → 𝜓) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | spim.1 | . . 3 ⊢ Ⅎ𝑥𝜓 | |
2 | 1 | nfri 1452 | . 2 ⊢ (𝜓 → ∀𝑥𝜓) |
3 | spim.2 | . 2 ⊢ (𝑥 = 𝑦 → (𝜑 → 𝜓)) | |
4 | 2, 3 | spimh 1665 | 1 ⊢ (∀𝑥𝜑 → 𝜓) |
Colors of variables: wff set class |
Syntax hints: → wi 4 ∀wal 1282 Ⅎwnf 1389 |
This theorem was proved from axioms: ax-1 5 ax-2 6 ax-mp 7 ax-ia1 104 ax-ia2 105 ax-ia3 106 ax-5 1376 ax-gen 1378 ax-ie1 1422 ax-ie2 1423 ax-4 1440 ax-i9 1463 ax-ial 1467 |
This theorem depends on definitions: df-bi 115 df-nf 1390 |
This theorem is referenced by: cbv3 1670 chvar 1680 spimv 1732 2spim 10577 |
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