Theorem sseldd 3000

Description: Membership inference from subclass relationship. (Contributed by NM, 14-Dec-2004.)

Hypotheses

Ref	Expression
sseld.1	⊢ (𝜑 → 𝐴 ⊆ 𝐵)
sseldd.2	⊢ (𝜑 → 𝐶 ∈ 𝐴)

Assertion

Ref	Expression
sseldd	⊢ (𝜑 → 𝐶 ∈ 𝐵)

Proof of Theorem sseldd

Step	Hyp	Ref	Expression
1		sseldd.2	. 2 ⊢ (𝜑 → 𝐶 ∈ 𝐴)
2		sseld.1	. . 3 ⊢ (𝜑 → 𝐴 ⊆ 𝐵)
3	2	sseld 2998	. 2 ⊢ (𝜑 → (𝐶 ∈ 𝐴 → 𝐶 ∈ 𝐵))
4	1, 3	mpd 13	1 ⊢ (𝜑 → 𝐶 ∈ 𝐵)

Syntax hints:   → wi 4   ∈ wcel 1433   ⊆ wss 2973

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-5 1376  ax-7 1377  ax-gen 1378  ax-ie1 1422  ax-ie2 1423  ax-8 1435  ax-11 1437  ax-4 1440  ax-17 1459  ax-i9 1463  ax-ial 1467  ax-i5r 1468  ax-ext 2063

This theorem depends on definitions:  df-bi 115  df-nf 1390  df-sb 1686  df-clab 2068  df-cleq 2074  df-clel 2077  df-in 2979  df-ss 2986

This theorem is referenced by:  frirrg  4105  ordtri2or2exmid  4314  riotass  5515  eroveu  6220  eroprf  6222  findcard2d  6375  findcard2sd  6376  suplub2ti  6414  nnppipi  6533  archnqq  6607  prarloclemlt  6683  suprubex  8029  suprzclex  8445  fzssp1  9085  elfzoelz  9157  fzofzp1  9236  fzostep1  9246  isermono  9457  bcm1k  9687  fimaxre2  10109  zssinfcl  10344