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Theorem symdifeq1 3846
Description: Equality theorem for symmetric difference. (Contributed by Scott Fenton, 24-Apr-2012.)
Assertion
Ref Expression
symdifeq1  |-  ( A  =  B  ->  ( A  /_\  C )  =  ( B  /_\  C ) )

Proof of Theorem symdifeq1
StepHypRef Expression
1 difeq1 3721 . . 3  |-  ( A  =  B  ->  ( A  \  C )  =  ( B  \  C
) )
2 difeq2 3722 . . 3  |-  ( A  =  B  ->  ( C  \  A )  =  ( C  \  B
) )
31, 2uneq12d 3768 . 2  |-  ( A  =  B  ->  (
( A  \  C
)  u.  ( C 
\  A ) )  =  ( ( B 
\  C )  u.  ( C  \  B
) ) )
4 df-symdif 3844 . 2  |-  ( A  /_\  C )  =  ( ( A  \  C
)  u.  ( C 
\  A ) )
5 df-symdif 3844 . 2  |-  ( B  /_\  C )  =  ( ( B  \  C
)  u.  ( C 
\  B ) )
63, 4, 53eqtr4g 2681 1  |-  ( A  =  B  ->  ( A  /_\  C )  =  ( B  /_\  C ) )
Colors of variables: wff setvar class
Syntax hints:    -> wi 4    = wceq 1483    \ cdif 3571    u. cun 3572    /_\ csymdif 3843
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-9 1999  ax-10 2019  ax-11 2034  ax-12 2047  ax-13 2246  ax-ext 2602
This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-tru 1486  df-ex 1705  df-nf 1710  df-sb 1881  df-clab 2609  df-cleq 2615  df-clel 2618  df-nfc 2753  df-ral 2917  df-rab 2921  df-v 3202  df-dif 3577  df-un 3579  df-symdif 3844
This theorem is referenced by:  symdifeq2  3847
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