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Theorem rncoeq 5389
Description: Range of a composition. (Contributed by NM, 19-Mar-1998.)
Assertion
Ref Expression
rncoeq (dom 𝐴 = ran 𝐵 → ran (𝐴𝐵) = ran 𝐴)

Proof of Theorem rncoeq
StepHypRef Expression
1 dmcoeq 5388 . 2 (dom 𝐵 = ran 𝐴 → dom (𝐵𝐴) = dom 𝐴)
2 eqcom 2629 . . 3 (dom 𝐴 = ran 𝐵 ↔ ran 𝐵 = dom 𝐴)
3 df-rn 5125 . . . 4 ran 𝐵 = dom 𝐵
4 dfdm4 5316 . . . 4 dom 𝐴 = ran 𝐴
53, 4eqeq12i 2636 . . 3 (ran 𝐵 = dom 𝐴 ↔ dom 𝐵 = ran 𝐴)
62, 5bitri 264 . 2 (dom 𝐴 = ran 𝐵 ↔ dom 𝐵 = ran 𝐴)
7 df-rn 5125 . . . 4 ran (𝐴𝐵) = dom (𝐴𝐵)
8 cnvco 5308 . . . . 5 (𝐴𝐵) = (𝐵𝐴)
98dmeqi 5325 . . . 4 dom (𝐴𝐵) = dom (𝐵𝐴)
107, 9eqtri 2644 . . 3 ran (𝐴𝐵) = dom (𝐵𝐴)
11 df-rn 5125 . . 3 ran 𝐴 = dom 𝐴
1210, 11eqeq12i 2636 . 2 (ran (𝐴𝐵) = ran 𝐴 ↔ dom (𝐵𝐴) = dom 𝐴)
131, 6, 123imtr4i 281 1 (dom 𝐴 = ran 𝐵 → ran (𝐴𝐵) = ran 𝐴)
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1483  ccnv 5113  dom cdm 5114  ran crn 5115  ccom 5118
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-9 1999  ax-10 2019  ax-11 2034  ax-12 2047  ax-13 2246  ax-ext 2602  ax-sep 4781  ax-nul 4789  ax-pr 4906
This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-3an 1039  df-tru 1486  df-ex 1705  df-nf 1710  df-sb 1881  df-eu 2474  df-mo 2475  df-clab 2609  df-cleq 2615  df-clel 2618  df-nfc 2753  df-rab 2921  df-v 3202  df-dif 3577  df-un 3579  df-in 3581  df-ss 3588  df-nul 3916  df-if 4087  df-sn 4178  df-pr 4180  df-op 4184  df-br 4654  df-opab 4713  df-cnv 5122  df-co 5123  df-dm 5124  df-rn 5125
This theorem is referenced by:  dfdm2  5667  foco  6125
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