Theorem sblbis 2404

Description: Introduce left biconditional inside of a substitution. (Contributed by NM, 19-Aug-1993.)

Hypothesis

Ref	Expression
sblbis.1	|- ( [ y / x ] ph <-> ps )

Assertion

Ref	Expression
sblbis	|- ( [ y / x ] ( ch <-> ph ) <-> ( [ y / x ] ch <-> ps ) )

Proof of Theorem sblbis

Step	Hyp	Ref	Expression
1		sbbi 2401	. 2 |- ( [ y / x ] ( ch <-> ph ) <-> ( [ y / x ] ch <-> [ y / x ] ph ) )
2		sblbis.1	. . 3 |- ( [ y / x ] ph <-> ps )
3	2	bibi2i 327	. 2 |- ( ( [ y / x ] ch <-> [ y / x ] ph ) <-> ( [ y / x ] ch <-> ps ) )
4	1, 3	bitri 264	1 |- ( [ y / x ] ( ch <-> ph ) <-> ( [ y / x ] ch <-> ps ) )

Syntax hints:   <-> wb 196   [wsb 1880

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-10 2019  ax-12 2047  ax-13 2246

This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-ex 1705  df-nf 1710  df-sb 1881

This theorem is referenced by:  sbie  2408  sb8eu  2503  sb8iota  5858  wl-sb8eut  33359