Theorem fvcofneq 6367

Description: The values of two function compositions are equal if the values of the composed functions are pairwise equal. (Contributed by AV, 26-Jan-2019.)

Assertion

Ref	Expression
fvcofneq	⊢ ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → ((𝐹 ∘ 𝐺)‘𝑋) = ((𝐻 ∘ 𝐾)‘𝑋)))

Distinct variable groups:   𝑥,𝐹   𝑥,𝐺   𝑥,𝐻   𝑥,𝐾   𝑥,𝑋

Allowed substitution hints:   𝐴(𝑥)   𝐵(𝑥)

Proof of Theorem fvcofneq

Step	Hyp	Ref	Expression
1		simpl 473	. . . 4 ⊢ ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → 𝐺 Fn 𝐴)
2		elin 3796	. . . . . 6 ⊢ (𝑋 ∈ (𝐴 ∩ 𝐵) ↔ (𝑋 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵))
3		simpl 473	. . . . . 6 ⊢ ((𝑋 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵) → 𝑋 ∈ 𝐴)
4	2, 3	sylbi 207	. . . . 5 ⊢ (𝑋 ∈ (𝐴 ∩ 𝐵) → 𝑋 ∈ 𝐴)
5	4	3ad2ant1 1082	. . . 4 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → 𝑋 ∈ 𝐴)
6		fvco2 6273	. . . 4 ⊢ ((𝐺 Fn 𝐴 ∧ 𝑋 ∈ 𝐴) → ((𝐹 ∘ 𝐺)‘𝑋) = (𝐹‘(𝐺‘𝑋)))
7	1, 5, 6	syl2an 494	. . 3 ⊢ (((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) ∧ (𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥))) → ((𝐹 ∘ 𝐺)‘𝑋) = (𝐹‘(𝐺‘𝑋)))
8		simpr 477	. . . . 5 ⊢ ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → 𝐾 Fn 𝐵)
9		simpr 477	. . . . . . 7 ⊢ ((𝑋 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵) → 𝑋 ∈ 𝐵)
10	2, 9	sylbi 207	. . . . . 6 ⊢ (𝑋 ∈ (𝐴 ∩ 𝐵) → 𝑋 ∈ 𝐵)
11	10	3ad2ant1 1082	. . . . 5 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → 𝑋 ∈ 𝐵)
12		fvco2 6273	. . . . 5 ⊢ ((𝐾 Fn 𝐵 ∧ 𝑋 ∈ 𝐵) → ((𝐻 ∘ 𝐾)‘𝑋) = (𝐻‘(𝐾‘𝑋)))
13	8, 11, 12	syl2an 494	. . . 4 ⊢ (((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) ∧ (𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥))) → ((𝐻 ∘ 𝐾)‘𝑋) = (𝐻‘(𝐾‘𝑋)))
14		fveq2 6191	. . . . . . 7 ⊢ ((𝐾‘𝑋) = (𝐺‘𝑋) → (𝐻‘(𝐾‘𝑋)) = (𝐻‘(𝐺‘𝑋)))
15	14	eqcoms 2630	. . . . . 6 ⊢ ((𝐺‘𝑋) = (𝐾‘𝑋) → (𝐻‘(𝐾‘𝑋)) = (𝐻‘(𝐺‘𝑋)))
16	15	3ad2ant2 1083	. . . . 5 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → (𝐻‘(𝐾‘𝑋)) = (𝐻‘(𝐺‘𝑋)))
17	16	adantl 482	. . . 4 ⊢ (((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) ∧ (𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥))) → (𝐻‘(𝐾‘𝑋)) = (𝐻‘(𝐺‘𝑋)))
18		id 22	. . . . . . . . . . . 12 ⊢ (𝐺 Fn 𝐴 → 𝐺 Fn 𝐴)
19		fnfvelrn 6356	. . . . . . . . . . . 12 ⊢ ((𝐺 Fn 𝐴 ∧ 𝑋 ∈ 𝐴) → (𝐺‘𝑋) ∈ ran 𝐺)
20	18, 4, 19	syl2anr 495	. . . . . . . . . . 11 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ 𝐺 Fn 𝐴) → (𝐺‘𝑋) ∈ ran 𝐺)
21	20	ex 450	. . . . . . . . . 10 ⊢ (𝑋 ∈ (𝐴 ∩ 𝐵) → (𝐺 Fn 𝐴 → (𝐺‘𝑋) ∈ ran 𝐺))
22		id 22	. . . . . . . . . . . 12 ⊢ (𝐾 Fn 𝐵 → 𝐾 Fn 𝐵)
23		fnfvelrn 6356	. . . . . . . . . . . 12 ⊢ ((𝐾 Fn 𝐵 ∧ 𝑋 ∈ 𝐵) → (𝐾‘𝑋) ∈ ran 𝐾)
24	22, 10, 23	syl2anr 495	. . . . . . . . . . 11 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ 𝐾 Fn 𝐵) → (𝐾‘𝑋) ∈ ran 𝐾)
25	24	ex 450	. . . . . . . . . 10 ⊢ (𝑋 ∈ (𝐴 ∩ 𝐵) → (𝐾 Fn 𝐵 → (𝐾‘𝑋) ∈ ran 𝐾))
26	21, 25	anim12d 586	. . . . . . . . 9 ⊢ (𝑋 ∈ (𝐴 ∩ 𝐵) → ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → ((𝐺‘𝑋) ∈ ran 𝐺 ∧ (𝐾‘𝑋) ∈ ran 𝐾)))
27		eleq1 2689	. . . . . . . . . . . 12 ⊢ ((𝐾‘𝑋) = (𝐺‘𝑋) → ((𝐾‘𝑋) ∈ ran 𝐾 ↔ (𝐺‘𝑋) ∈ ran 𝐾))
28	27	eqcoms 2630	. . . . . . . . . . 11 ⊢ ((𝐺‘𝑋) = (𝐾‘𝑋) → ((𝐾‘𝑋) ∈ ran 𝐾 ↔ (𝐺‘𝑋) ∈ ran 𝐾))
29	28	anbi2d 740	. . . . . . . . . 10 ⊢ ((𝐺‘𝑋) = (𝐾‘𝑋) → (((𝐺‘𝑋) ∈ ran 𝐺 ∧ (𝐾‘𝑋) ∈ ran 𝐾) ↔ ((𝐺‘𝑋) ∈ ran 𝐺 ∧ (𝐺‘𝑋) ∈ ran 𝐾)))
30		elin 3796	. . . . . . . . . . 11 ⊢ ((𝐺‘𝑋) ∈ (ran 𝐺 ∩ ran 𝐾) ↔ ((𝐺‘𝑋) ∈ ran 𝐺 ∧ (𝐺‘𝑋) ∈ ran 𝐾))
31	30	biimpri 218	. . . . . . . . . 10 ⊢ (((𝐺‘𝑋) ∈ ran 𝐺 ∧ (𝐺‘𝑋) ∈ ran 𝐾) → (𝐺‘𝑋) ∈ (ran 𝐺 ∩ ran 𝐾))
32	29, 31	syl6bi 243	. . . . . . . . 9 ⊢ ((𝐺‘𝑋) = (𝐾‘𝑋) → (((𝐺‘𝑋) ∈ ran 𝐺 ∧ (𝐾‘𝑋) ∈ ran 𝐾) → (𝐺‘𝑋) ∈ (ran 𝐺 ∩ ran 𝐾)))
33	26, 32	sylan9 689	. . . . . . . 8 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋)) → ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → (𝐺‘𝑋) ∈ (ran 𝐺 ∩ ran 𝐾)))
34		fveq2 6191	. . . . . . . . . . . 12 ⊢ (𝑥 = (𝐺‘𝑋) → (𝐹‘𝑥) = (𝐹‘(𝐺‘𝑋)))
35		fveq2 6191	. . . . . . . . . . . 12 ⊢ (𝑥 = (𝐺‘𝑋) → (𝐻‘𝑥) = (𝐻‘(𝐺‘𝑋)))
36	34, 35	eqeq12d 2637	. . . . . . . . . . 11 ⊢ (𝑥 = (𝐺‘𝑋) → ((𝐹‘𝑥) = (𝐻‘𝑥) ↔ (𝐹‘(𝐺‘𝑋)) = (𝐻‘(𝐺‘𝑋))))
37	36	rspcva 3307	. . . . . . . . . 10 ⊢ (((𝐺‘𝑋) ∈ (ran 𝐺 ∩ ran 𝐾) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → (𝐹‘(𝐺‘𝑋)) = (𝐻‘(𝐺‘𝑋)))
38	37	eqcomd 2628	. . . . . . . . 9 ⊢ (((𝐺‘𝑋) ∈ (ran 𝐺 ∩ ran 𝐾) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → (𝐻‘(𝐺‘𝑋)) = (𝐹‘(𝐺‘𝑋)))
39	38	ex 450	. . . . . . . 8 ⊢ ((𝐺‘𝑋) ∈ (ran 𝐺 ∩ ran 𝐾) → (∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥) → (𝐻‘(𝐺‘𝑋)) = (𝐹‘(𝐺‘𝑋))))
40	33, 39	syl6 35	. . . . . . 7 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋)) → ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → (∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥) → (𝐻‘(𝐺‘𝑋)) = (𝐹‘(𝐺‘𝑋)))))
41	40	com23 86	. . . . . 6 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋)) → (∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥) → ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → (𝐻‘(𝐺‘𝑋)) = (𝐹‘(𝐺‘𝑋)))))
42	41	3impia 1261	. . . . 5 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → (𝐻‘(𝐺‘𝑋)) = (𝐹‘(𝐺‘𝑋))))
43	42	impcom 446	. . . 4 ⊢ (((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) ∧ (𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥))) → (𝐻‘(𝐺‘𝑋)) = (𝐹‘(𝐺‘𝑋)))
44	13, 17, 43	3eqtrrd 2661	. . 3 ⊢ (((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) ∧ (𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥))) → (𝐹‘(𝐺‘𝑋)) = ((𝐻 ∘ 𝐾)‘𝑋))
45	7, 44	eqtrd 2656	. 2 ⊢ (((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) ∧ (𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥))) → ((𝐹 ∘ 𝐺)‘𝑋) = ((𝐻 ∘ 𝐾)‘𝑋))
46	45	ex 450	1 ⊢ ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → ((𝐹 ∘ 𝐺)‘𝑋) = ((𝐻 ∘ 𝐾)‘𝑋)))

Syntax hints:   → wi 4   ↔ wb 196   ∧ wa 384   ∧ w3a 1037   = wceq 1483   ∈ wcel 1990  ∀wral 2912   ∩ cin 3573  ran crn 5115   ∘ ccom 5118   Fn wfn 5883  ‘cfv 5888

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-8 1992  ax-9 1999  ax-10 2019  ax-11 2034  ax-12 2047  ax-13 2246  ax-ext 2602  ax-sep 4781  ax-nul 4789  ax-pow 4843  ax-pr 4906

This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-3an 1039  df-tru 1486  df-ex 1705  df-nf 1710  df-sb 1881  df-eu 2474  df-mo 2475  df-clab 2609  df-cleq 2615  df-clel 2618  df-nfc 2753  df-ne 2795  df-ral 2917  df-rex 2918  df-rab 2921  df-v 3202  df-sbc 3436  df-dif 3577  df-un 3579  df-in 3581  df-ss 3588  df-nul 3916  df-if 4087  df-sn 4178  df-pr 4180  df-op 4184  df-uni 4437  df-br 4654  df-opab 4713  df-id 5024  df-xp 5120  df-rel 5121  df-cnv 5122  df-co 5123  df-dm 5124  df-rn 5125  df-res 5126  df-ima 5127  df-iota 5851  df-fun 5890  df-fn 5891  df-fv 5896

This theorem is referenced by:  fvcosymgeq  17849