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Mirrors > Home > ILE Home > Th. List > elabg | Unicode version |
Description: Membership in a class abstraction, using implicit substitution. Compare Theorem 6.13 of [Quine] p. 44. (Contributed by NM, 14-Apr-1995.) |
Ref | Expression |
---|---|
elabg.1 |
Ref | Expression |
---|---|
elabg |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | nfcv 2219 | . 2 | |
2 | nfv 1461 | . 2 | |
3 | elabg.1 | . 2 | |
4 | 1, 2, 3 | elabgf 2736 | 1 |
Colors of variables: wff set class |
Syntax hints: wi 4 wb 103 wceq 1284 wcel 1433 cab 2067 |
This theorem was proved from axioms: ax-1 5 ax-2 6 ax-mp 7 ax-ia1 104 ax-ia2 105 ax-ia3 106 ax-io 662 ax-5 1376 ax-7 1377 ax-gen 1378 ax-ie1 1422 ax-ie2 1423 ax-8 1435 ax-10 1436 ax-11 1437 ax-i12 1438 ax-bndl 1439 ax-4 1440 ax-17 1459 ax-i9 1463 ax-ial 1467 ax-i5r 1468 ax-ext 2063 |
This theorem depends on definitions: df-bi 115 df-tru 1287 df-nf 1390 df-sb 1686 df-clab 2068 df-cleq 2074 df-clel 2077 df-nfc 2208 df-v 2603 |
This theorem is referenced by: elab2g 2740 intmin3 3663 finds 4341 elxpi 4379 ovelrn 5669 indpi 6532 peano5nnnn 7058 peano5nni 8042 |
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