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| Mirrors > Home > ILE Home > Th. List > 3eqtrrd | GIF version | ||
| Description: A deduction from three chained equalities. (Contributed by NM, 4-Aug-2006.) (Proof shortened by Andrew Salmon, 25-May-2011.) |
| Ref | Expression |
|---|---|
| 3eqtrd.1 | ⊢ (𝜑 → 𝐴 = 𝐵) |
| 3eqtrd.2 | ⊢ (𝜑 → 𝐵 = 𝐶) |
| 3eqtrd.3 | ⊢ (𝜑 → 𝐶 = 𝐷) |
| Ref | Expression |
|---|---|
| 3eqtrrd | ⊢ (𝜑 → 𝐷 = 𝐴) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | 3eqtrd.1 | . . 3 ⊢ (𝜑 → 𝐴 = 𝐵) | |
| 2 | 3eqtrd.2 | . . 3 ⊢ (𝜑 → 𝐵 = 𝐶) | |
| 3 | 1, 2 | eqtrd 2113 | . 2 ⊢ (𝜑 → 𝐴 = 𝐶) |
| 4 | 3eqtrd.3 | . 2 ⊢ (𝜑 → 𝐶 = 𝐷) | |
| 5 | 3, 4 | eqtr2d 2114 | 1 ⊢ (𝜑 → 𝐷 = 𝐴) |
| Colors of variables: wff set class |
| Syntax hints: → wi 4 = wceq 1284 |
| This theorem was proved from axioms: ax-1 5 ax-2 6 ax-mp 7 ax-ia1 104 ax-ia2 105 ax-ia3 106 ax-5 1376 ax-gen 1378 ax-4 1440 ax-17 1459 ax-ext 2063 |
| This theorem depends on definitions: df-bi 115 df-cleq 2074 |
| This theorem is referenced by: nnanq0 6648 1idprl 6780 1idpru 6781 axcnre 7047 fseq1p1m1 9111 expmulzap 9522 expubnd 9533 subsq 9581 bcm1k 9687 bcpasc 9693 crim 9745 rereb 9750 bezoutlema 10388 bezoutlemb 10389 eucialg 10441 |
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