Theorem opabssxp 4432

Description: An abstraction relation is a subset of a related cross product. (Contributed by NM, 16-Jul-1995.)

Assertion

Ref	Expression
opabssxp	⊢ {⟨𝑥, 𝑦⟩ ∣ ((𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵) ∧ 𝜑)} ⊆ (𝐴 × 𝐵)

Distinct variable groups:   𝑥,𝑦,𝐴   𝑥,𝐵,𝑦

Allowed substitution hints:   𝜑(𝑥,𝑦)

Proof of Theorem opabssxp

Step	Hyp	Ref	Expression
1		simpl 107	. . 3 ⊢ (((𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵) ∧ 𝜑) → (𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵))
2	1	ssopab2i 4032	. 2 ⊢ {⟨𝑥, 𝑦⟩ ∣ ((𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵) ∧ 𝜑)} ⊆ {⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵)}
3		df-xp 4369	. 2 ⊢ (𝐴 × 𝐵) = {⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵)}
4	2, 3	sseqtr4i 3032	1 ⊢ {⟨𝑥, 𝑦⟩ ∣ ((𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵) ∧ 𝜑)} ⊆ (𝐴 × 𝐵)

Syntax hints:   ∧ wa 102   ∈ wcel 1433   ⊆ wss 2973  {copab 3838   × cxp 4361

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-io 662  ax-5 1376  ax-7 1377  ax-gen 1378  ax-ie1 1422  ax-ie2 1423  ax-8 1435  ax-10 1436  ax-11 1437  ax-i12 1438  ax-bndl 1439  ax-4 1440  ax-17 1459  ax-i9 1463  ax-ial 1467  ax-i5r 1468  ax-ext 2063

This theorem depends on definitions:  df-bi 115  df-nf 1390  df-sb 1686  df-clab 2068  df-cleq 2074  df-clel 2077  df-nfc 2208  df-in 2979  df-ss 2986  df-opab 3840  df-xp 4369

This theorem is referenced by:  brab2ga  4433  dmoprabss  5606  ecopovsym  6225  ecopovtrn  6226  ecopover  6227  ecopovsymg  6228  ecopovtrng  6229  ecopoverg  6230  enqex  6550  ltrelnq  6555  enq0ex  6629  ltrelpr  6695  enrex  6914  ltrelsr  6915  ltrelre  7001  ltrelxr  7173  dvdszrcl  10200